Question

6£®ÈçͼËùʾ£¬×óÔòÓÐ10ÔÑÔ²ÐÎÏßȦ£¬Æä°ë¾¶Îªr=1.0cm£¬ÏßȦµÄµç×è²»¼Æ£¬ÏßȦÖÐÓд¹Ö±ÓÚÏßȦƽÃæµÄ±ä»¯´Å³¡£¬´Å¸ÐӦǿ¶ÈBµÄ±ä»¯ÂÊ$\frac{¡÷A}{¡÷t}=100\sqrt{2}$¦Ðsin100¦Ðt£¬ÏßȦÓëÀíÏë±äѹÆ÷µÄÔ­ÏßȦÏàÁ¬£¬ÀíÏë±äѹÆ÷µÄ¸ºÏßȦÁ½¶ËÁ¬ÓÐÒ»¸ö×èֵΪ40¦¸µÄ¶¨Öµµç×èºÍÒ»¸öµç×èÏ䣬ÀíÏë±äѹÆ÷Ô­£¬¸ºÏßȦÔÑÊýÖ®±ÈΪ1£º10£¬£¨È¡¦Ð²=10£©£®
£¨1£©µç×èÏäµÄ×èֵΪÁãʱ£¨¿ªÂ·£©£¬Ô­ÏßȦÊäÈëµÄµç¹¦Âʶà´ó£¿
£¨2£©µç×èÏäµÄ×èֵΪ¶à´óʱ£¬µçÁ÷±íµÄ¶ÁÊýΪ5A£¿

Answer 1

·ÖÎö £¨1£©¸ù¾Ý·¨À­µÚµç´Å¸ÐÓ¦¶¨ÂÉÇó³öÏßȦ²úÉúµÄ¸ÐÓ¦µç¶¯ÊÆ£¬¸ù¾Ý±äѹÆ÷µçѹÓëÔÑÊýµÄ¹ØϵÇó³ö¸±ÏßȦÁ½¶ËµÄµçѹ£¬Çó³öµç×èÏ俪·ʱ£¬¸±ÏßȦµÄÊä³ö¹¦ÂÊ£¬¼´¿ÉÇó³öÔ­ÏßȦÊäÈëµÄµç¹¦ÂÊ£»
£¨2£©¸ù¾ÝµçÁ÷ÓëÔÑÊý³É·´±ÈÇó³ö¸±ÏßȦµÄ×ܵçÁ÷£¬ÔÙ¸ù¾Ý²¢Áªµç·µÄÌصãÇó³öµç×èÏäµÄ×èÖµ

½â´ð ½â£º£¨1£©¸ÐÓ¦µç¶¯ÊÆΪ£º
$E=n\frac{¡÷B}{¡÷t}S$=$10¡Á100\sqrt{2}¦Ðsin100¦Ðt¡Á¦Ð¡Á£¨1¡Á1{0}_{\;}^{-2}£©_{\;}^{2}$=$\sqrt{2}sin100¦Ðt£¨V£©$
Ô­ÏßȦµçѹµÄÓÐЧֵΪ£º
${U}_{1}^{\;}=\frac{\sqrt{2}}{\sqrt{2}}=1V$
¸±ÏßȦÁ½¶ËµçѹΪ£º
${U}_{2}^{\;}=10{U}_{1}^{\;}=10V$
µç×èÏ俪·£¬¸±ÏßȦÊä³öµÄµç¹¦ÂÊΪ£º
${P}_{2}^{\;}=\frac{{U}_{2}^{2}}{R}=\frac{1{0}_{\;}^{2}}{40}=2.5W$
ËùÒÔÔ­ÏßȦÊäÈëµÄµç¹¦ÂÊ2.5W
£¨2£©¸ù¾ÝµçÁ÷ÓëÔÑÊý³É·´±È£¬ÓУº
$\frac{{I}_{1}^{\;}}{{I}_{2}^{\;}}=\frac{{n}_{2}^{\;}}{{n}_{1}^{\;}}$
µÃ¸±ÏßȦµçÁ÷Ϊ£º
${I}_{2}^{\;}=\frac{{n}_{1}^{\;}}{{n}_{2}^{\;}}{I}_{1}^{\;}=\frac{1}{10}¡Á5=\frac{1}{2}A$
${I}_{2}^{\;}=\frac{{U}_{2}^{\;}}{R¡ä}+\frac{{U}_{2}^{\;}}{R}$
$\frac{1}{2}=\frac{10}{R¡ä}+\frac{10}{40}$
½âµÃ£ºR¡ä=40¦¸
´ð£º£¨1£©µç×èÏäµÄ×èֵΪÁãʱ£¨¿ªÂ·£©£¬Ô­ÏßȦÊäÈëµÄµç¹¦ÂÊ2.5W
£¨2£©µç×èÏäµÄ×èֵΪ40¦¸Ê±£¬µçÁ÷±íµÄ¶ÁÊýΪ5A

µãÆÀ ±¾Ì⿼²éµÄ֪ʶµã½Ï¶à£¬¿¼²éÁË·¨À­µÚµç´Å¸ÐÓ¦¶¨ÂÉ£¬±äѹÆ÷µÄ±äѹºÍ±äÁ÷µÄÔ­Àí£¬ÒÔ¼°´®²¢Áªµç·µÄÌص㣬ҪעÒâÕýÏÒ½»Á÷µçÓÐЧֵÓë×î´óÖµÖ®¼äµÄ¹Øϵ£®