Question

11£®Îª²â¶¨Ä³¾É¸Éµç³ØµÄµç¶¯ÊƺÍÄÚ×裬ʵÑéÊÒÌṩÁËÈçÏÂÆ÷²Ä£º
A£®¾É¸Éµç³Ø1½Ú
B£®µçѹ±í£¨ÊÓΪÀíÏëµçѹ±í£¬Á¿³Ì0¡«3V£©
C£®µç×èÏäR£¨0¡«999.9¦¸£©
D£®¶¨Öµµç×èR₀=10¦¸
E£®¶àÓõç±í
F£®¿ª¹Ø¡¢µ¼ÏßÈô¸É

£¨1£©¼×ͬѧֱ½ÓʹÓöàÓõç±íµÄÖ±Á÷2.5Vµµ²âÁ¿¸Ãµç³ØµÄµç¶¯ÊÆ£¬¶ÁÊýÈçͼ¼×Ëùʾ£¬Ôò¸Ãͬѧ²âµÃµÄµç¶¯ÊÆE=1.45V£¬´Ë²âÁ¿Öµ±È¾É¸Éµç³Øµç¶¯ÊƵÄÕæʵֵƫС£¨Ìî¡°Æ«´ó¡±»òÕß¡°Æ«Ð¡¡±£©£¬ÆäÔ­ÒòÊÇ·üÌرí²âµÄÊÇ·¶Ëµçѹ£¬Ð¡ÓÚµç³ØµÄµç¶¯ÊÆ£®
£¨2£©ÒÒͬѧ½«¸Éµç³Ø½ÓÈëÈçͼÒÒËùʾµÄµç·£¬¹æ·¶²Ù×÷µÃµ½Èçͼ±ûËùʾµÄͼÏó£®Í¼ÏóµÄбÂÊΪk£¬ÔÚ×ÝÖáÉϵĽؾàΪb£¬Ôò¸Ã¸Éµç³ØµÄµç¶¯ÊÆE=$\frac{1}{k{R}_{0}}$£¬ÄÚ×èr=$\frac{b}{k}$-R₀£¨ÓÃk¡¢b¡¢R₀±íʾ£©£®

Answer 1

·ÖÎö £¨1£©¸ù¾Ýµçѹ±íµÄ¶ÁÊý·½·¨¿ÉÃ÷È·¶ÔÓ¦µÄµç¶¯ÊÆ£»¸ù¾Ýµçѹ±íÄÚ×èµÄÓ°Ïì¼´¿ÉÃ÷È·²âÁ¿Îó²î£»
£¨2£©¸ù¾Ý±ÕºÏµç·ŷķ¶¨ÂɽøÐзÖÎö¸ù¾ÝͼÏóµÄÐÔÖÊ¿ÉÃ÷È·µçÔ´µÄµç¶¯ÊƺÍÄÚµç×裮

½â´ð ½â£º£¨1£©Á¿³ÌΪ2.5V£¬Ôò×îС·Ö¶ÈΪ0.05V£¬ÔòÆä¶ÁÊýΪ1.45V£»
ÓÉÓÚµçѹ±íÄÚ×è²»ÊÇÎÞÇî´ó£¬¹ÊËù²âӦΪ·¶Ëµçѹ£¬¹Ê²âÁ¿ÖµÎªÂ·¶Ëµçѹ£¬¹Ê²âÁ¿ÖµÆ«Ð¡£»
£¨2£©¸ù¾ÝͼÒÒ¿ÉÖªÁ½µç×è´®Áª£¬µçѹ±í²âÁ¿R₀Á½¶ËµÄµçѹ£¬ÔòÓɱպϵç·ŷķ¶¨ÂÉ¿ÉÖª£º
U=$\frac{E}{{R}_{0}+r+R}$R₀£» 
±äÐοɺÍÊÇ£º$\frac{1}{U}$=$\frac{1}{E}$+$\frac{r}{E{R}_{0}}$+$\frac{R}{E{R}_{0}}$£» 
¸ù¾ÝͼÏó¿ÉÖª£¬b=$\frac{1}{E}$+$\frac{r}{E{R}_{0}}$
K=$\frac{1}{E{R}_{0}}$
½âµÃ£ºE=$\frac{1}{K{R}_{0}}$£» r=$\frac{b}{k}$-R₀£» 
¹Ê´ð°¸Îª£º£¨1£©1.45£»Æ«Ð¡£»·üÌرí²âµÄÊÇ·¶Ëµçѹ£¬Ð¡ÓÚµç³ØµÄµç¶¯ÊÆ£»£¨2£©$\frac{1}{K{R}_{0}}$£»$\frac{b}{k}$-R₀

µãÆÀ ±¾Ì⿼²é²âÁ¿µç¶¯ÊƺÍÄÚµç×èµÄʵÑ飬ҪעÒâÃ÷ȷʵÑéÔ­Àí£¬Ã÷ȷʹÓöàÓõç±í²âÁ¿µç×èµÄ»ù±¾·½·¨£¬Í¬Ê±ÕÆÎÕ¸ù¾ÝͼÏó·ÖÎöÊý¾ÝµÄ»ù±¾·½·¨£®