Question

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Answer 1

·ÖÎö ¢Ù´Ë¹ý³ÌΪµÈѹ¹ý³Ì£¬·Ö±ðÇó³ö³õĩ״̬µÄÌå»ý£¬ÔÙ¸ù¾Ý$\frac{{V}_{0}^{\;}}{{T}_{0}^{\;}}=\frac{{V}_{1}^{\;}}{{T}_{1}^{\;}}$ÁÐʽÇó½â¼´¿É£»
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$\frac{{V}_{0}^{\;}}{{T}_{0}^{\;}}=\frac{{V}_{1}^{\;}}{{T}_{1}^{\;}}$¡­¢Ù
${V}_{0}^{\;}={S}_{A}^{\;}h+{S}_{B}^{\;}h$=1.5h¡­¢Ú
${V}_{1}^{\;}$=${S}_{A}^{\;}h+2{S}_{B}^{\;}h$=2h¡­¢Û
ÁªÁ¢¢Ù¢Ú¢ÛµÃ£º$\frac{1.5h}{300}=\frac{2h}{{T}_{1}^{\;}}$
½âµÃ£º${T}_{1}^{\;}=400K$
¢ÚÆøÌå×öµÈÈݱ仯£¬ÓɲéÀí¶¨Âɵãº
$\frac{{p}_{1}^{\;}}{{T}_{1}^{\;}}=\frac{{p}_{2}^{\;}}{{T}_{2}^{\;}}$
×î³õ£¬¶ÔB»îÈûÓУº${p}_{1}^{\;}{S}_{B}^{\;}={p}_{0}^{\;}{S}_{B}^{\;}+{m}_{B}^{\;}g$
½âµÃ£º${p}_{1}^{\;}=2.4¡Á1{0}_{\;}^{5}{p}_{a}^{\;}$
»îÈûÒª¶¯Ê±£¬¶ÔA»îÈûÓУº${p}_{2}^{\;}{S}_{A}^{\;}$=${p}_{0}^{\;}{S}_{A}^{\;}+{m}_{A}^{\;}g+f$£¬
½âµÃ£º${p}_{2}^{\;}=2.7¡Á1{0}_{\;}^{5}{p}_{a}^{\;}$
ËùÒÔÓУº$\frac{2.4¡Á1{0}_{\;}^{5}}{400}=\frac{2.7¡Á1{0}_{\;}^{5}}{{T}_{2}^{\;}}$
½âµÃ£º${T}_{2}^{\;}=450K$
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¢Úµ±Æø¸×AÖеĻîÈû¸ÕÒª»¬¶¯Ê±£¬ÆøÌåµÄζÈ${T}_{2}^{\;}$Ϊ450K

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