Question

2£®Ò»ÖÊÁ¿ÎªmµÄСÇòÒÔ³õ¶¯ÄÜE_k0´ÓµØÃæÊúÖ±ÏòÉÏÅ׳ö£¬ÒÑÖªÉÏÉý¹ý³ÌÖÐÊܵ½×èÁ¦f×÷Óã¬Í¼ÖÐÁ½ÌõͼÏß·Ö±ð±íʾСÇòÔÚÉÏÉý¹ý³ÌÖж¯ÄÜ¡¢ÖØÁ¦ÊÆÄÜÖеÄijһ¸öÓëÆäÉÏÉý¸ß¶ÈÖ®¼äµÄ¹Øϵ£¬£¨ÒÔµØÃæΪÁãÊÆÄÜÃ棬h₀±íʾÉÏÉýµÄ×î´ó¸ß¶È£¬Í¼ÉÏ×ø±êÊý¾ÝÖеÄkΪ³£ÊýÇÒÂú×ã0£¼k£¼l£©£®ÔòÓÉͼ¿ÉÖª£¬ÏÂÁнáÂÛÕýÈ·µÄÊÇ£¨¡¡¡¡£©

• A£® ¢Ù¡¢¢Ú·Ö±ð±íʾµÄÊǶ¯ÄÜ¡¢ÖØÁ¦ÊÆÄÜËæÉÏÉý¸ß¶ÈµÄͼÏó
• B£® ÉÏÉý¹ý³ÌÖÐ×èÁ¦´óСºã¶¨ÇÒf=kmg
• C£® ÉÏÉý¸ß¶Èh=$\frac{k+1}{k+2}$h₀ʱ£¬ÖØÁ¦ÊÆÄܺͶ¯ÄÜÏàµÈ
• D£® ÉÏÉý¸ß¶Èh=$\frac{1}{2}$h₀ʱ£¬¶¯ÄÜÓëÖØÁ¦ÊÆÄÜÖ®²îΪ$\frac{k}{2}$mgh₀

Answer 1

·ÖÎö £¨1£©¶¯ÄÜ´óСµÄÓ°ÏìÒòËØ£ºÖÊÁ¿¡¢Ëٶȣ®ÖÊÁ¿Ô½´ó£¬ËÙ¶ÈÔ½´ó£¬¶¯ÄÜÔ½´ó£®
£¨2£©ÖØÁ¦ÊÆÄÜ´óСµÄÓ°ÏìÒòËØ£ºÖÊÁ¿¡¢±»¾ÙµÃ¸ß¶È£®ÖÊÁ¿Ô½´ó£¬¸ß¶ÈÔ½¸ß£¬ÖØÁ¦ÊÆÄÜÔ½´ó£®
£¨3£©»úеÄÜ=¶¯ÄÜ+ÊÆÄÜ£®ÎïÌåûÓз¢Éúµ¯ÐÔÐαäʱ£¬²»¿¼Âǵ¯ÐÔÊÆÄÜ£®

½â´ð ½â£ºA¡¢¸ù¾Ý¶¯Äܶ¨Àí¿ÉÖªÉÏÉý¸ß¶ÈÔ½´ó£¬¶¯ÄÜԽС£¬ÖØÁ¦ÊÆÄÜÔ½´ó£¬¹Ê¢Ù¡¢¢Ú·Ö±ð±íʾÖØÁ¦ÊÆÄÜ¡¢¶¯ÄÜËæÉÏÉý¸ß¶ÈµÄͼÏ󣬹ÊA´íÎó£»
B¡¢´Ó¢ÚͼÏß¿´£¬ÖØÁ¦ÊÆÄÜ¡¢¶¯ÄÜËæן߶ȵı仯³ÉÏßÐÔ¹Øϵ£¬¹ÊºÏÁ¦ºã¶¨£¬Êܵ½µÄ×èÁ¦´óСºã¶¨£¬Óɹ¦ÄܹØϵ¿ÉÖª´ÓÅ׳öµ½×î¸ßµãµÄ¹ý³ÌÖлúеÄܵļõÉÙÁ¿µÈÓÚ×èÁ¦µÄ¹¦µÄ´óС£¬ÓÉ¢ÚͼÏß¿ÉÖª£ºfh₀=E_k0-$\frac{{E}_{k0}}{k+1}$£¬ÇÒÓÉ¢ÙͼÏ߸ù¾Ý¶¯Äܶ¨Àí¿ÉÖªE_k0=£¨mg+f£©h₀£¬½âµÃf=kmg£¬¹ÊBÕýÈ·£»
 C¡¢Éèh¸ß¶ÈʱÖØÁ¦ÊÆÄܺͶ¯ÄÜÏàµÈ£¬¢ÙͼÏߵĺ¯Êý·½³ÌΪE_k=E_k0-£¨mg+f£©h£¬¢ÚͼÏߵĺ¯Êý·½³ÌΪE_P=$\frac{{E}_{k0}}{£¨k+1£©{h}_{0}}•h$£¬
ÁîE_k=E_P£¬¼°E_k0=£¨mg+f£©h₀ºÍf=kmg£¬ÁªÁ¢½âµÃh=$\frac{k+1}{k+2}$h₀£¬CÕýÈ·£»Í¬Àí¿ÉµÃDÕýÈ·
¹ÊÑ¡£ºBCD

µãÆÀ £¨1£©ÕÆÎÕ¶¯ÄܺÍÖØÁ¦ÊÆÄÜ´óСµÄÓ°ÏìÒòËØ£¬¸ù¾ÝͼÏóÄÜÈ·¶¨¶¯ÄܺÍÊÆÄܵĴóС£®
£¨2£©¸ù¾Ý¡°E=E_K+E_P¡±¼ÆËã»úеÄܵĴóС£®