Question

3£®Èçͼ£¬Ò»¸öÖÊÁ¿ÎªmµÄTÐÍ»îÈûÔÚÆø¸×ÄÚ·â±ÕÒ»¶¨Á¿µÄÀíÏëÆøÌ壬»îÈûÌå»ý¿ÉºöÂÔ²»¼Æ£¬¾àÆø¸×µ×²¿h_o´¦Á¬½ÓÒ»UÐÎϸ¹Ü£¨¹ÜÄÚÆøÌåµÄÌå»ýºöÂÔ²»¼Æ£©£®³õʼʱ£¬·â±ÕÆøÌåζÈΪT₀£¬»îÈû¾àÀëÆø¸×µ×²¿Îª1.5h₀£¬Á½±ßË®ÒøÖù´æÔڸ߶ȲÒÑ֪ˮÒøÃܶÈΪ¦Ñ£¬´óÆøѹǿΪP₀£¬Æø¸×ºá½ØÃæ»ýΪS£¬»îÈûÊúÖ±²¿·Ö¸ßΪ1.2h₀£¬ÖØÁ¦¼ÓËÙ¶ÈΪg£¬Çó£º
£¨i£©Í¨¹ýÖÆÀä×°ÖûºÂý½µµÍÆøÌåζȣ¬µ±Î¶ÈΪ¶àÉÙʱÁ½±ßË®ÒøÃæÇ¡ºÃÏàƽ£»
£¨ii£©´Ó¿ªÊ¼ÖÁÁ½Ë®ÒøÃæÇ¡ºÃÏàƽµÄ¹ý³ÌÖУ¬ÈôÆøÌå·Å³öµÄÈÈÁ¿ÎªQ£¬ÇóÆøÌåÄÚÄܵı仯£®

Answer 1

·ÖÎö £¨1£©¶Ô·â±ÕÆøÌåÓÉÀíÏëÆøÌå״̬·½³ÌÇó½â
£¨2£©¸ù¾ÝW=p¡÷VÇóµÈѹ¹ý³ÌÖÐÆøÌå×ö¹¦£¬¸ù¾ÝÈÈÁ¦Ñ§µÚÒ»¶¨ÂÉÇóÆøÌåÄÚÄܵı仯Á¿£®

½â´ð ½â£º£¨i£©³õ̬ʱ£¬¶Ô»îÈûÊÜÁ¦·ÖÎö£¬¿ÉÇóÆøÌåѹǿ${p}_{1}^{\;}={p}_{0}^{\;}+\frac{mg}{S}$¡¡¢Ù
Ìå»ýV₁=1.5h₀S£¬Î¶ÈT₁=T₀
ҪʹÁ½±ßË®ÒøÃæÏàƽ£¬Æø¸×ÄÚÆøÌåµÄѹǿP₂=P₀£¬
´Ëʱ»îÈû϶ËÒ»¶¨ÓëÆø¸×µ×½Ó´¥£¬V₂=1.2h₀
Éè´ËʱζÈΪT₂£¬ÓÉÀíÏëÆøÌå״̬·½³ÌÓÐ$\frac{{p}_{1}^{\;}{V}_{1}^{\;}}{{T}_{1}^{\;}}=\frac{{p}_{2}^{\;}{V}_{2}^{\;}}{{T}_{2}^{\;}}$¡¡¢Ú
µÃ£º${T}_{2}^{\;}=\frac{4{p}_{0}^{\;}{T}_{0}^{\;}S}{5{p}_{0}^{\;}S+5mg}$¡¡¡¡¡¡¡¡¡¡¡¡¡¡   
£¨ii£©´Ó¿ªÊ¼ÖÁ»îÈûÊúÖ±²¿·ÖÇ¡ÓëÆø¸×µ×½Ó´¥£¬ÆøÌåѹǿ²»±ä£¬Íâ½ç¶ÔÆøÌå×ö¹¦
W=P₁¡÷V=£¨${p}_{0}^{\;}+\frac{mg}{S}$£©¡Á0.3h₀S    ¢Û
ÓÉÈÈÁ¦Ñ§µÚÒ»¶¨ÂÉÓС÷U=W+Q¡¡       ¢Ü
µÃ£º¡÷U=0.3£¨${p}_{0}^{\;}+\frac{mg}{S}$£©h₀S-Q¡¡¡¡¡¡¡¡¡¡    
´ð£º£¨i£©Í¨¹ýÖÆÀä×°ÖûºÂý½µµÍÆøÌåζȣ¬µ±Î¶ÈΪ$\frac{4{p}_{0}^{\;}{T}_{0}^{\;}S}{5{p}_{0}^{\;}S+5mg}$ʱÁ½±ßË®ÒøÃæÇ¡ºÃÏàƽ£»
£¨ii£©´Ó¿ªÊ¼ÖÁÁ½Ë®ÒøÃæÇ¡ºÃÏàƽµÄ¹ý³ÌÖУ¬ÈôÆøÌå·Å³öµÄÈÈÁ¿ÎªQ£¬ÆøÌåÄÚÄܵı仯Ϊ$0.3£¨{p}_{0}^{\;}+\frac{mg}{S}£©{h}_{0}^{\;}S-Q$£®

µãÆÀ ±¾Ì⿼²éÁËÀíÏëÆøÌå״̬·½³ÌºÍÈÈÁ¦Ñ§µÚÒ»¶¨ÂɵÄÓ¦Óã¬ÕâÁ½¸ö¿¼µãÒ»Ö±ÊǸ߿¼µÄÈȵ㣬ӦÊìÁ·ÕÆÎÕ£®