ÔÚÏàͬµÄʱ¼äÄÚ£¬Ä³ÕýÏÒ½»Á÷µçͨ¹ýÒ»×èֵΪ100WµÄµç×è²úÉúµÄÈÈÁ¿£¬ÓëÒ»µçÁ÷Ç¿¶ÈΪ3AµÄÖ±Á÷µçͨ¹ýͬһ×èÖµµÄµç×è²úÉúµÄÈÈÁ¿ÏàµÈ£¬Ôò£¨¡¡£©

A£®´Ë½»Á÷µçµÄµçÁ÷µÄÓÐЧֵΪ3A£¬×î´óֵΪ3A

B£®´Ë½»Á÷µçµÄµçÁ÷µÄÓÐЧֵΪ3A£¬×î´óֵΪ6A

C£®µç×èÁ½¶ËµÄ½»Á÷µçѹµÄÓÐЧֵΪ300V£¬×î´óֵΪ300V

D£®µç×èÁ½¶ËµÄ½»Á÷µçѹµÄÓÐЧֵΪ300V£¬×î´óֵΪ600V

 

´ð°¸£ºAC
Ìáʾ£º

½»Á÷µç»ù±¾±íÕ÷Á¿µÄÕÆÎÕºÍÔËÓÃ

 


Á·Ï°²áϵÁдð°¸
Ïà¹ØÏ°Ìâ

¿ÆÄ¿£º¸ßÖÐÎïÀí À´Ô´£º ÌâÐÍ£º

Æû³µÕýÒÔv1=10m/sµÄËÙ¶ÈÔÚƽֱ¹«Â·ÉÏÐÐÊ»£¬Í»È»·¢ÏÖÕýÇ°·½ÓÐÒ»Á¾×ÔÐгµÒÔv2=4m/sµÄËÙ¶È×÷ͬ·½ÏòµÄÔÈËÙÖ±ÏßÔ˶¯£¬Æû³µÁ¢¼´¹Ø±ÕÓÍÃÅ×÷¼ÓËٶȴóСΪa=0.6m/s2µÄÔȼõËÙÔ˶¯£¬Æû³µÇ¡ºÃûÓÐÅöÉÏ×ÔÐгµ£¬Çó¹Ø±ÕÓÍÃÅʱÆû³µÓë×ÔÐгµµÄ¾àÀ룮
ijͬѧÊÇÕâÑù½âµÄ£ºÆû³µ¹Ø±ÕÓÍÃźóµÄ»¬ÐÐʱ¼äºÍ»¬ÐоàÀë·Ö±ðΪt=
v
 
1
a
£¬s1=
v
2
1
2a
ÔÚÏàͬʱ¼äÄÚ£¬×ÔÐгµµÄÇ°½øµÄ¾àÀëΪs2=v2t£¬¹Ø±ÕÓÍÃÅʱÆû³µÓë×ÔÐгµµÄ¾àÀëΪs=s1-s2¡­ÄãÈÏΪÕâλͬѧµÄ½â·¨ÊÇ·ñºÏÀí£¿ÈôºÏÀí£¬ÇëÍê³É¼ÆË㣻Èô²»ºÏÀí£¬ÇëÓÃÄã×Ô¼ºµÄ·½·¨Ëã³öÕýÈ·½á¹û£®

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖÐÎïÀí À´Ô´£º ÌâÐÍ£º

Ò»ÎïÌåÔÚ´Ö²ÚµÄˮƽÃæÉÏ×ÔÓÉ»¬ÐУ¬´Óijʱ¿ÌÆð¶Ô¸ÃÎïÌåÊ©¼ÓÒ»ºãÁ¦F£¬ÔòÔڴ˺óµÄÒ»¶Îʱ¼äÄÚ£¨¡¡¡¡£©

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖÐÎïÀí À´Ô´£º ÌâÐÍ£ºÔĶÁÀí½â

£¨1£©Ä³Í¬Ñ§ÀûÓÃÈçͼ1ËùʾµÄ×°Öã¬Ì½¾¿Ë®Æ½ÃæÉÏÁ½ÎïÌå¼ä»¬¶¯Ä¦²ÁÁ¦fÓëÕýѹÁ¦FNÖ®¼äµÄ¹Øϵ£¬°´ÕÕÕýÈ·µÄ²Ù×÷²½Ö裬Êʵ±Ìí¼Ó¹³Â룬ʹÆäÄܹ»´ø¶¯Ð¡³µÏòÓÒÔ˶¯£®
¢ÙʵÑéÖÐС³µµÄÔ˶¯ÊÇ·ñ±ØÐëΪÔÈËÙÖ±ÏßÔ˶¯£¿
´ð£º
·ñ
·ñ
£¨Ìî¡°ÊÇ¡±»òÕß¡°·ñ¡±£©
¢ÚʵÑéÖÐÓÃÀ´±íʾ»¬¶¯Ä¦²ÁÁ¦f´óСµÄÊÇ£º
D
D
£»±íʾÁ½ÎïÌå¼äÕýѹÁ¦FN´óСµÄÊÇ
C
C
£¨ÌîÑ¡Ïî·ûºÅ£©
A£®¹³ÂëÖØÁ¦   B£®Ð¡³µ¡¢Ä¾¿éºÍíÀÂëÖØÁ¦   C£®Ä¾¿éºÍíÀÂë×ÜÖØÁ¦   D£®µ¯»É³Ó¶ÁÊý
£¨2£©Èçͼ2ËùʾΪ¼ÓËٶȴ«¸ÐÆ÷×°Öã¬Á½¸öÍêÈ«ÏàͬµÄÇᵯ»ÉÖ®¼äÁ¬½ÓÒ»»¬¿é£¬Á½Çᵯ»É·Ö±ðÓë×°ÖÃ×ó¡¢ÓÒ¶ËÁ¬½Ó£¬»¬¿é´¦ÓÚ×°ÖÃÄڹ⻬ˮƽÃæÉÏ£¬»¬¿éÓë±ä×èÆ÷µÄ½ðÊô»¬Æ¬P¹Ì¶¨ÔÚÒ»Æ𣬵çѹ±íͨ¹ýµ¼ÏßÒ»¶ËÓë±ä×èÆ÷ÖеãOÁ¬½Ó£¬ÁíÒ»¶ËÓ뻬ƬPÁ¬½Ó£¬×°Öô¦ÓÚ¾²Ö¹×´Ì¬£¬»¬Æ¬PλÓÚ±ä×èÆ÷ÕýÖÐÑ룮ÒÑÖªÁ½¸öµ¯»ÉµÄ¾¢¶ÈϵÊý¾ùΪk£¬»¬¿éÖÊÁ¿Îªm£¬µçÔ´µç¶¯ÊÆΪE£¬ÄÚ×èΪr£¬±ä×èÆ÷×Ü×èֵΪR0¡¢È«³¤Îªl£¬µçѹ±íΪÀíÏëµçѹ±í£¬²»¼Æ»¬Æ¬ÖÊÁ¿ºÍ¿ÕÆø×èÁ¦£¬ÏÖÈÃ×°ÖÃÔÚˮƽ·½Ïò×÷ÔÈËÙÖ±ÏßÔ˶¯£¬µçѹ±í¶ÁÊýÔÚºÏÊʵķ¶Î§ÄÚ£¬Èç¹û½«µçѹ±íÉϿ̶ȸÄΪÏàÓ¦¼ÓËÙ¶ÈÊýÖµ£¬Ôò³ÉΪ¼ÓËٶȼƣ®
¢Ùµçѹ±íµÄʾÊý×î´óÖµ²»µÃСÓÚ
R0E
2(R0+r)
R0E
2(R0+r)

¢Úµ±¼ÓËٶȴóСΪaʱ£¬µçѹ±í¶ÁÊýΪU£¬Çëд³öaµÄ±í´ïʽa=
2kl(R0+r)U
mR0E
2kl(R0+r)U
mR0E

¢ÛÈôµçԴʹÓýϳ¤Ê±¼äºó£¬µç¶¯ÊÆE¼õС£¬ÄÚ×èrÔö´ó£¬¸Ã¼ÓËٶȼƶÁÊýÓëʵ¼ÊÖµ±È½Ï£º
ƫС
ƫС
£¨Ìî¡°Æ«´ó¡±¡¢¡°Æ«Ð¡¡±»ò¡°Ò»Ö¡±£©

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖÐÎïÀí À´Ô´£º ÌâÐÍ£ºÔĶÁÀí½â

µÚ¾Å²¿·Ö ÎȺãµçÁ÷

µÚÒ»½² »ù±¾ÖªÊ¶½éÉÜ

µÚ°Ë²¿·Ö¡¶ÎȺãµçÁ÷¡·°üÀ¨Á½´ó¿é£ºÒ»ÊÇ¡°ºã¶¨µçÁ÷¡±£¬¶þÊÇ¡°ÎïÖʵĵ¼µçÐÔ¡±¡£Ç°ÕßÊǶÔÓڵ緵ÄÍⲿ¼ÆË㣬ºóÕßÔòÊÇÉîÈë΢¹Û¿Õ¼ä£¬È¥½âÊ͵çÁ÷µÄ³ÉÒòºÍ±È½Ï²»Í¬ÖÖÀàµÄÎïÖʵ¼µçµÄÇéÐÎÓÐʲôÇø±ð¡£

Ó¦¸Ã˵£¬µÚÒ»¿éµÄ֪ʶºÍ¸ß¿¼¿¼¸Ù¶ÔÓ¦µÃ±È½ÏºÃ£¬ÉµÄ²¿·ÖÊǶԸ´Ôӵ緵ļÆË㣨ÒýÈëÁËһЩеĴ¦ÀíÊֶΣ©¡£µÚ¶þ¿éËäÊÇȫеÄÄÚÈÝ£¬µ«½ü¼¸ÄêµÄ¿¼ÊÔÒѾ­ºÜÉÙÉæ¼°£¬ÒÔÖÁÓںܶà°ÂÈüÅàѵ×ÊÁ϶¼°ÑËüɾµôÁË¡£¼øÓÚÔÚ°ÂÈü¿¼¸ÙÖÐÕⲿ·ÖÄÚÈÝ»¹±£Áô×Å£¬ÎÒÃÇ»¹ÊÇÏë´ÖÂԵؽéÉÜһϡ£

Ò»¡¢Å·Ä·¶¨ÂÉ

1¡¢µç×趨ÂÉ

a¡¢µç×趨ÂÉ R = ¦Ñ

b¡¢½ðÊôµÄµç×èÂÊ ¦Ñ = ¦Ñ0£¨1 + ¦Át£©

2¡¢Å·Ä·¶¨ÂÉ

a¡¢Íâµç·ŷķ¶¨ÂÉ U = IR £¬Ë³×ŵçÁ÷·½ÏòµçÊƽµÂä

b¡¢º¬Ô´µç·ŷķ¶¨ÂÉ

ÔÚÈçͼ8-1ËùʾµÄº¬Ô´µç·ÖУ¬´ÓAµãµ½Bµã£¬×ñÕÕÔ­Ôò£º¢ÙÓöµç×裬˳µçÁ÷·½ÏòµçÊƽµÂ䣨ÄæµçÁ÷·½ÏòµçÊÆÉý¸ß£©¢ÚÓöµçÔ´£¬Õý¼«µ½¸º¼«µçÊƽµÂ䣬¸º¼«µ½Õý¼«µçÊÆÉý¸ß£¨ÓëµçÁ÷·½ÏòÎ޹أ©£¬¿ÉÒԵõ½ÒÔϹØϵ

UA ? IR ? ¦Å ? Ir = UB 

Õâ¾ÍÊǺ¬Ô´µç·ŷķ¶¨ÂÉ¡£

c¡¢±ÕºÏµç·ŷķ¶¨ÂÉ

ÔÚͼ8-1ÖУ¬Èô½«A¡¢BÁ½µã¶Ì½Ó£¬ÔòµçÁ÷·½ÏòÖ»¿ÉÄÜÏò×󣬺¬Ô´µç·ŷķ¶¨ÂɳÉΪ

UA + IR ? ¦Å + Ir = UB = UA

¼´ ¦Å = IR + Ir £¬»ò I = 

Õâ¾ÍÊDZպϵç·ŷķ¶¨ÂÉ¡£ÖµµÃ×¢ÒâµÄµÄÊÇ£º¢Ù¶ÔÓÚ¸´Ôӵ緣¬¡°¸É·µçÁ÷I¡±²»ÄÜ×ö¾ø¶ÔµÄÀí½â£¨ÈκÎÒª¿¼²ìµÄÒ»Ìõ·¾ù¿ÉÊÓΪ¸É·£©£»¢ÚµçÔ´µÄ¸ÅÄîÒ²ÊÇÏà¶ÔµÄ£¬Ëü¿ÉÒÔÊǶà¸öµçÔ´µÄ´®¡¢²¢Áª£¬Ò²¿ÉÒÔÊǵçÔ´ºÍµç×è×é³ÉµÄϵͳ£»¢ÛÍâµç×èR¿ÉÒÔÊǶà¸öµç×èµÄ´®¡¢²¢Áª»ò»ìÁª£¬µ«²»ÄÜ°üº¬µçÔ´¡£

¶þ¡¢¸´Ôӵ緵ļÆËã

1¡¢´÷άÄ϶¨Àí£ºÒ»¸öÓɶÀÁ¢Ô´¡¢ÏßÐÔµç×è¡¢ÏßÐÔÊÜ¿ØÔ´×é³ÉµÄ¶þ¶ËÍøÂ磬¿ÉÒÔÓÃÒ»¸öµçѹԴºÍµç×è´®ÁªµÄ¶þ¶ËÍøÂçÀ´µÈЧ¡££¨ÊÂʵÉÏ£¬Ò²¿ÉµÈЧΪ¡°µçÁ÷Ô´ºÍµç×è²¢ÁªµÄµÄ¶þ¶ËÍøÂ硱¡ª¡ªÕâ¾Í³ÉÁËŵ¶Ù¶¨Àí¡££©

Ó¦Ó÷½·¨£ºÆäµÈЧµç·µÄµçѹԴµÄµç¶¯ÊƵÈÓÚÍøÂçµÄ¿ªÂ·µçѹ£¬Æä´®Áªµç×èµÈÓÚ´Ó¶ËÅ¥¿´½øÈ¥¸ÃÍøÂçÖÐËùÓжÀÁ¢Ô´ÎªÁãֵʱµÄµÈЧµç×è¡£

2¡¢»ù¶û»ô·ò£¨¿ËÏ£¿Æ·ò£©¶¨ÂÉ

a¡¢»ù¶û»ô·òµÚÒ»¶¨ÂÉ£ºÔÚÈÎһʱ¿ÌÁ÷Èëµç·ÖÐijһ·Ö½ÚµãµÄµçÁ÷Ç¿¶ÈµÄ×ܺͣ¬µÈÓڴӸõãÁ÷³öµÄµçÁ÷Ç¿¶ÈµÄ×ܺ͡£

ÀýÈ磬ÔÚͼ8-2ÖУ¬Õë¶Ô½ÚµãP £¬ÓÐ

I2 + I3 = I1 

»ù¶û»ô·òµÚÒ»¶¨ÂÉÒ²±»³ÆΪ¡°½ÚµãµçÁ÷¶¨ÂÉ¡±£¬ËüÊǵçºÉÊܺ㶨ÂÉÔÚµç·ÖеľßÌåÌåÏÖ¡£

¶ÔÓÚ»ù¶û»ô·òµÚÒ»¶¨ÂɵÄÀí½â£¬½üÀ´ÒѾ­ÍØչΪ£ºÁ÷Èëµç·ÖÐijһ¡°°üÈݿ顱µÄµçÁ÷Ç¿¶ÈµÄ×ܺͣ¬µÈÓڴӸá°°üÈݿ顱Á÷³öµÄµçÁ÷Ç¿¶ÈµÄ×ܺ͡£

b¡¢»ù¶û»ô·òµÚ¶þ¶¨ÂÉ£ºÔÚµç·ÖÐÈÎÈ¡Ò»±ÕºÏ»Ø·£¬²¢¹æ¶¨ÕýµÄÈÆÐз½Ïò£¬ÆäÖе綯ÊƵĴúÊýºÍ£¬µÈÓÚ¸÷²¿·Öµç×裨ÔÚ½»Á÷µç·ÖÐΪ×迹£©ÓëµçÁ÷Ç¿¶È³Ë»ýµÄ´úÊýºÍ¡£

ÀýÈ磬ÔÚͼ8-2ÖУ¬Õë¶Ô±ÕºÏ»Ø·¢Ù £¬ÓÐ

¦Å3 ? ¦Å2 = I3 ( r3 + R2 + r2 ) ? I2R2 

»ù¶û»ô·òµÚ¶þ¶¨ÂÉÊÂʵÉÏÊǺ¬Ô´²¿·Öµç·ŷķ¶¨ÂɵıäÌ壨¡îͬѧÃÇ¿ÉÒÔÁз½³Ì UP = ¡­ = UPµÃµ½ºÍÉÏÃæÍêÈ«ÏàͬµÄʽ×Ó£©¡£

3¡¢Y?¦¤±ä»»

ÔÚÄÑÒÔ¿´Çå´®¡¢²¢Áª¹ØϵµÄµç·ÖУ¬½øÐС°YÐÍ?¦¤ÐÍ¡±µÄÏ໥ת»»³£³£ÊDZØÒªµÄ¡£ÔÚͼ8-3ËùʾµÄµç·ÖÐ

¡îͬѧÃÇ¿ÉÒÔÖ¤Ã÷¦¤¡ú YµÄ½áÂÛ¡­

Rc = 

Rb = 

Ra = 

Y¡ú¦¤µÄ±ä»»ÉÔÉÔ¸´ÔÓһЩ£¬µ«ÎÒÃÇÈÔÈ»¿ÉÒԵõ½

R1 = 

R2 = 

R3 = 

Èý¡¢µç¹¦ºÍµç¹¦ÂÊ

1¡¢µçÔ´

ʹÆäËûÐÎʽµÄÄÜÁ¿×ª±äΪµçÄܵÄ×°Öá£Èç·¢µç»ú¡¢µç³ØµÈ¡£·¢µç»úÊǽ«»úеÄÜת±äΪµçÄÜ£»¸Éµç³Ø¡¢Ðîµç³ØÊǽ«»¯Ñ§ÄÜת±äΪµçÄÜ£»¹âµç³ØÊǽ«¹âÄÜת±äΪµçÄÜ£»Ô­×Óµç³ØÊǽ«Ô­×Ӻ˷ÅÉäÄÜת±äΪµçÄÜ£»ÔÚµç×ÓÉ豸ÖУ¬ÓÐʱҲ°Ñ±ä»»µçÄÜÐÎʽµÄ×°Öã¬ÈçÕûÁ÷Æ÷µÈ£¬×÷ΪµçÔ´¿´´ý¡£

µçÔ´µç¶¯Êƶ¨ÒåΪµçÔ´µÄ¿ªÂ·µçѹ£¬ÄÚ×èÔò¶¨ÒåΪûÓе綯ÊÆʱµç·ͨ¹ýµçÔ´ËùÓöµ½µÄµç×è¡£¾Ý´Ë²»ÄÑÍƳöÏàͬµçÔ´´®Áª¡¢²¢Áª£¬ÉõÖÁ²»Í¬µçÔ´´®Áª¡¢²¢ÁªµÄʱµÄµç¶¯ÊƺÍÄÚ×èµÄÖµ¡£

ÀýÈ磬µç¶¯ÊÆ¡¢ÄÚ×è·Ö±ðΪ¦Å1 ¡¢r1ºÍ¦Å2 ¡¢r2µÄµçÔ´²¢Áª£¬¹¹³ÉµÄеçÔ´µÄµç¶¯ÊƦźÍÄÚ×èr·Ö±ðΪ£¨¡îʦÉú¹²Í¬ÍƵ¼¡­£©

¦Å = 

r = 

2¡¢µç¹¦¡¢µç¹¦ÂÊ

µçÁ÷ͨ¹ýµç·ʱ£¬µç³¡Á¦¶ÔµçºÉ×÷µÄ¹¦½Ð×öµç¹¦W¡£µ¥Î»Ê±¼äÄڵ糡Á¦Ëù×÷µÄ¹¦½Ð×öµç¹¦ÂÊP ¡£

¼ÆËãʱ£¬Ö»ÓÐW = UItºÍP = UIÊÇÍêȫûÓÐÌõ¼þµÄ£¬¶ÔÓÚ²»º¬Ô´µÄ´¿µç×裬µç¹¦ºÍ½¹¶úÈÈÖغϣ¬µç¹¦ÂÊÔòºÍÈȹ¦ÂÊÖغϣ¬ÓÐW = I2Rt = tºÍP = I2R = ¡£

¶Ô·Ç´¿µç×èµç·£¬µç¹¦ºÍµçÈȵĹØϵÒÀ¾ÝÄÜÁ¿Êغ㶨ÂÉÇó½â¡£ 

ËÄ¡¢ÎïÖʵĵ¼µçÐÔ

ÔÚ²»Í¬µÄÎïÖÊÖУ¬µçºÉ¶¨ÏòÒƶ¯ÐγɵçÁ÷µÄ¹æÂɲ¢²»ÊÇÍêÈ«ÏàͬµÄ¡£

1¡¢½ðÊôÖеĵçÁ÷

¼´Í¨³£ËùνµÄ²»º¬Ô´´¿µç×èÖеĵçÁ÷£¬¹æÂÉ×ñ´Ó¡°Íâµç·ŷķ¶¨ÂÉ¡±¡£

2¡¢ÒºÌåµ¼µç

Äܹ»µ¼µçµÄÒºÌå½Ðµç½âÒº£¨²»°üÀ¨ÒºÌ¬½ðÊô£©¡£µç½âÒºÖÐÀë½â³öµÄÕý¸ºÀë×Óµ¼µçÊÇÒºÌåµ¼µçµÄÌص㣨È磺ÁòËáÍ­·Ö×ÓÔÚͨ³£Çé¿öÏÂÊǵçÖÐÐԵģ¬µ«ËüÔÚÈÜÒºÀïÊÜË®·Ö×ÓµÄ×÷ÓþͻáÀë½â³ÉÍ­Àë×ÓCu2+ºÍÁòËá¸ùÀë×ÓS£¬ËüÃÇÔڵ糡Á¦µÄ×÷ÓÃ϶¨ÏòÒƶ¯ÐγɵçÁ÷£©¡£

ÔÚµç½âÒºÖмӵ糡ʱ£¬ÔÚÁ½¸öµç¼«ÉÏ£¨»òµç¼«ÅÔ£©Í¬Ê±²úÉú»¯Ñ§·´Ó¦µÄ¹ý³Ì½Ð×÷¡°µç½â¡±¡£µç½âµÄ½á¹ûÊÇÔÚÁ½¸ö¼«°åÉÏ£¨»òµç¼«ÅÔ£©Éú³ÉеÄÎïÖÊ¡£

ÒºÌåµ¼µç×ñ´Ó·¨À­µÚµç½â¶¨ÂÉ¡ª¡ª

·¨À­µÚµç½âµÚÒ»¶¨ÂÉ£ºµç½âʱÔڵ缫ÉÏÎö³ö»òÈܽâµÄÎïÖʵÄÖÊÁ¿ºÍµçÁ÷Ç¿¶È¡¢¸úͨµçʱ¼ä³ÉÕý±È¡£±í´ïʽ£ºm = kIt £½ KQ £¨Ê½ÖÐQΪÎö³öÖÊÁ¿ÎªmµÄÎïÖÊËùÐèÒªµÄµçÁ¿£»KΪµç»¯µ±Á¿£¬µç»¯µ±Á¿µÄÊýÖµËæ×ű»Îö³öµÄÎïÖÊÖÖÀà¶ø²»Í¬£¬Ä³ÖÖÎïÖʵĵ绯µ±Á¿ÔÚÊýÖµÉϵÈÓÚͨ¹ý1CµçÁ¿Ê±Îö³öµÄ¸ÃÖÖÎïÖʵÄÖÊÁ¿£¬Æ䵥λΪkg/C¡££©

·¨À­µÚµç½âµÚ¶þ¶¨ÂÉ£ºÎïÖʵĵ绯µ±Á¿KºÍËüµÄ»¯Ñ§µ±Á¿³ÉÕý±È¡£Ä³ÖÖÎïÖʵĻ¯Ñ§µ±Á¿ÊǸÃÎïÖʵÄĦ¶ûÖÊÁ¿M£¨¿ËÔ­×ÓÁ¿£©ºÍËüµÄ»¯ºÏ¼ÛnµÄ±ÈÖµ£¬¼´ K =  £¬¶øFΪ·¨À­µÚ³£Êý£¬¶ÔÈκÎÎïÖʶ¼Ïàͬ£¬F = 9.65¡Á104C/mol ¡£

½«Á½¸ö¶¨ÂÉÁªÁ¢¿ÉµÃ£ºm = Q ¡£

3¡¢ÆøÌåµ¼µç

ÆøÌåµ¼µçÊǺܲ»ÈÝÒ׵ģ¬ËüµÄÇ°ÌáÊÇÆøÌåÖбØÐë³öÏÖ¿ÉÒÔ¶¨ÏòÒƶ¯µÄÀë×Ó»òµç×Ó¡£°´ÕÕ¡°ÔØÁ÷×Ó¡±³öÏÖ·½Ê½µÄ²»Í¬£¬¿ÉÒÔ°ÑÆøÌå·Åµç·ÖΪÁ½´óÀࡪ¡ª

a¡¢±»¼¤·Åµç

ÔÚµØÃæ·ÅÉäÐÔÔªËصķøÕÕÒÔ¼°×ÏÍâÏߺÍÓîÖæÉäÏߵȵÄ×÷ÓÃÏ£¬»áÓÐÉÙÁ¿ÆøÌå·Ö×Ó»òÔ­×Ó±»µçÀ룬»òÔÚÓÐЩµÆ¹ÜÄÚ£¬Í¨µçµÄµÆË¿Ò²»á·¢Éäµç×Ó£¬ÕâЩ¡°ÔØÁ÷×Ó¡±¾ù»áÔڵ糡Á¦×÷ÓÃϲúÉú¶¨ÏòÒƶ¯ÐγɵçÁ÷¡£ÕâÖÖÇé¿öϵĵçÁ÷Ò»°ã±È½Ï΢Èõ£¬ÇÒ×ñ´ÓÅ·Ä·¶¨ÂÉ¡£µäÐ͵ı»¼¤·ÅµçÇéÐÎÓÐ

b¡¢×Ô¼¤·Åµç

µ«ÊÇ£¬µ±µç³¡×㹻ǿ£¬µç×Ó¶¯ÄÜ×ã¹»´ó£¬ËüÃǺÍÖÐÐÔÆøÌåÏàÅöײʱ£¬¿ÉÒÔʹÖÐÐÔ·Ö×ÓµçÀ룬¼´ËùνÅöײµçÀ롣ͬʱ£¬ÔÚÕýÀë×ÓÏòÒõ¼«Ô˶¯Ê±£¬ÓÉÓÚÒԺܴóµÄËÙ¶Èײµ½Òõ¼«ÉÏ£¬»¹¿ÉÄÜ´ÓÒõ¼«±íÃæÉÏ´ò³öµç×ÓÀ´£¬ÕâÖÖÏÖÏó³ÆΪ¶þ´Îµç×Ó·¢Éä¡£ÅöײµçÀëºÍ¶þ´Îµç×Ó·¢ÉäʹÆøÌåÖÐÔں̵ܶÄʱ¼äÄÚ³öÏÖÁË´óÁ¿µÄµç×ÓºÍÕýÀë×Ó£¬µçÁ÷ÒàѸËÙÔö´ó¡£ÕâÖÖÏÖÏó±»³ÆΪ×Ô¼¤·Åµç¡£×Ô¼¤·Åµç²»×ñ´ÓÅ·Ä·¶¨ÂÉ¡£

³£¼ûµÄ×Ô¼¤·ÅµçÓÐËÄ´óÀࣺ»Ô¹â·Åµç¡¢»¡¹â·Åµç¡¢»ð»¨·Åµç¡¢µçÔηŵ硣

4¡¢³¬µ¼ÏÖÏó

¾Ý½ðÊôµç×èÂʺÍζȵĹØϵ£¬µç×èÂÊ»áËæ×ÅζȵĽµµÍºÍ½µµÍ¡£µ±µç×èÂʽµÎªÁãʱ£¬³ÆΪ³¬µ¼ÏÖÏó¡£µç×èÂÊΪÁãʱ¶ÔÓ¦µÄζȳÆΪÁÙ½çζȡ£³¬µ¼ÏÖÏóÊ×ÏÈÊǺÉÀ¼ÎïÀíѧ¼Ò°ºÄá˹·¢Ïֵġ£

³¬µ¼µÄÓ¦ÓÃÇ°¾°ÊÇÏÔ¶øÒ×¼ûÇÒÏ൱¹ãÀ«µÄ¡£µ«ÓÉÓÚÒ»°ã½ðÊôµÄÁÙ½çζÈÒ»°ã¶¼·Ç³£µÍ£¬¹Ê²úÒµ»¯µÄ¼ÛÖµ²»´ó£¬ÎªÁ˽â¾öÕâ¸öì¶Ü£¬¿Æѧ¼ÒÃÇÖÂÁ¦ÓÚÑ°ÕÒ»òºÏ³ÉÁÙ½çζȱȽÏÇкÏʵ¼ÊµÄ²ÄÁϾͳÉÁ˵±½ñÇ°ÑؿƼ¼µÄÒ»¸öÈÈÃÅÁìÓò¡£µ±Ç°ÈËÃǵÄÑо¿Ö÷ÒªÊǼ¯ÖÐÔںϳɲÄÁÏ·½Ã棬ÁÙ½çζÈÒѾ­³¬¹ý100K£¬µ±È»£¬Õâ¸öζȾà²úÒµ»¯µÄÆÚÍûÖµ»¹ºÜÔ¶¡£

5¡¢°ëµ¼Ìå

°ëµ¼ÌåµÄµç×èÂʽçÓÚµ¼ÌåºÍ¾øÔµÌåÖ®¼ä£¬ÇÒ¦Ñ

²é¿´´ð°¸ºÍ½âÎö>>

ͬ²½Á·Ï°²á´ð°¸