(1)¿É¼ûÐÇAËùÊÜ°µÐÇBµÄÒýÁ¦FA¿ÉµÈЧΪλÓÚOµã´¦ÖÊÁ¿Îªm¡äµÄÐÇÌå(ÊÓΪÖʵã)¶ÔËüµÄÒýÁ¦£¬ÉèAºÍBµÄÖÊÁ¿·Ö±ðΪm1¡¢m2£¬ÊÔÇóm¡ä(ÓÃm1¡¢m2±íʾ)£»
(2)Çó°µÐÇBµÄÖÊÁ¿m2Óë¿É¼ûÐÇAµÄËÙÂÊv¡¢ÔËÐÐÖÜÆÚTºÍÖÊÁ¿m1Ö®¼äµÄ¹Øϵʽ£»
(3)ºãÐÇÑÝ»¯µ½Ä©ÆÚ£¬Èç¹ûÆäÖÊÁ¿´óÓÚÌ«ÑôÖÊÁ¿msµÄ2±¶£¬Ëü½«ÓпÉÄܳÉΪºÚ¶´¡£Èô¿É¼ûÐÇAµÄËÙÂÊv=2.7¡Á105m/s£¬ÔËÐÐÖÜÆÚT=4.7¦Ð¡Á104s£¬ÖÊÁ¿m1=6ms£¬ÊÔͨ¹ý¹ÀËãÀ´ÅжϰµÐÇBÓпÉÄÜÊǺڶ´Âð?(G=6.67¡Á10-11N¡¤m2/kg2£¬ms=2.0¡Á1030kg)
£¨1£©
£¨2£©
£¨3£©°µÐÇBÓпÉÄÜÊǺڶ´¡£
½âÎö:£¨1£©ÉèA¡¢BµÄÔ²¹ìµÀ°ë¾¶·Ö±ðΪr1¡¢r2£¬ÓÉÌâÒâÖª£¬A¡¢B×öÔÈËÙÔ²ÖÜÔ˶¯µÄ½ÇËÙ¶ÈÏàͬ£¬ÉèÆäΪ¦Ø¡£ÓÉÅ£¶ÙÔ˶¯¶¨ÂÉ£¬ÓÐ
FA=m1¦Ø2r1
FB= m2¦Ø2r2
FA=FB
ÉèA¡¢BÖ®¼äµÄ¾àÀëΪr£¬ÓÖr=r1+r2£¬ÓÉÉÏÊö¸÷ʽµÃ
r=r1 ¢Ù
ÓÉÍòÓÐÒýÁ¦¶¨ÂÉ£¬ÓÐ
FA=G
½«¢Ù´úÈëµÃ
FA=G
Áî
FA=G
±È½Ï¿ÉµÃ
m¡ä= ¢Ú
£¨2£©ÓÉÅ£¶ÙµÚ¶þ¶¨ÂÉ£¬ÓÐ
G=m1 ¢Û
ÓֿɼûÐÇAµÄ¹ìµÀ°ë¾¶
r1= ¢Ü
ÓÉ¢Ú¢Û¢Üʽ½âµÃ
¢Ý
£¨3£©½«m1=6ms´úÈë¢Ýʽ£¬µÃ
´úÈëÊý¾ÝµÃ
=3.5ms ¢Þ
Éèm2=nms£¨n£¾0£©£¬½«Æä´úÈë¢Þʽ£¬µÃ
ms=3.5ms ¢ß
¿É¼û£¬µÄÖµËænµÄÔö´ó¶øÔö´ó£¬ÊÔÁîn=2£¬µÃ
ms=0.125ms£¼3.5ms ¢à
Èôʹ¢ßʽ³ÉÁ¢£¬Ôòn±Ø´óÓÚ2£¬¼´°µÐÇBµÄÖÊÁ¿m2±Ø´óÓÚ2ms£¬Óɴ˵óö½áÂÛ£º°µÐÇBÓпÉÄÜÊǺڶ´¡£
Ä꼶 | ¸ßÖÐ¿Î³Ì | Ä꼶 | ³õÖÐ¿Î³Ì |
¸ßÒ» | ¸ßÒ»Ãâ·Ñ¿Î³ÌÍƼö£¡ | ³õÒ» | ³õÒ»Ãâ·Ñ¿Î³ÌÍƼö£¡ |
¸ß¶þ | ¸ß¶þÃâ·Ñ¿Î³ÌÍƼö£¡ | ³õ¶þ | ³õ¶þÃâ·Ñ¿Î³ÌÍƼö£¡ |
¸ßÈý | ¸ßÈýÃâ·Ñ¿Î³ÌÍƼö£¡ | ³õÈý | ³õÈýÃâ·Ñ¿Î³ÌÍƼö£¡ |
¿ÆÄ¿£º¸ßÖÐÎïÀí À´Ô´£º ÌâÐÍ£º
²é¿´´ð°¸ºÍ½âÎö>>
¿ÆÄ¿£º¸ßÖÐÎïÀí À´Ô´£º ÌâÐÍ£º
²é¿´´ð°¸ºÍ½âÎö>>
¿ÆÄ¿£º¸ßÖÐÎïÀí À´Ô´£º ÌâÐÍ£º
ͼ5-4-3
(1)¿É¼ûÐÇAËùÊÜ°µÐÇBµÄÒýÁ¦Fa¿ÉµÈЧΪλÓÚOµã´¦ÖÊÁ¿Îªm¡äµÄÐÇÌå(ÊÓΪÖʵã)¶ÔËüµÄÒýÁ¦£¬ÉèAºÍBµÄÖÊÁ¿·Ö±ðΪm1¡¢m2£¬ÊÔÇóm¡ä(ÓÃm1¡¢m2±íʾ);
(2)Çó°µÐÇBµÄÖÊÁ¿m2Óë¿É¼ûÐÇAµÄËÙÂÊv¡¢ÔËÐÐÖÜÆÚTºÍÖÊÁ¿m1Ö®¼äµÄ¹Øϵʽ£»
(3)ºãÐÇÑÝ»¯µ½Ä©ÆÚ£¬Èç¹ûÆäÖÊÁ¿´óÓÚÌ«ÑôÖÊÁ¿msµÄ2±¶£¬Ëü½«ÓпÉÄܳÉΪºÚ¶´.Èô¿É¼ûÐÇAµÄËÙÂÊv=2.7¡Á105 m/s£¬ÔËÐÐÖÜÆÚT=4.7¦Ð¡Á104 s£¬ÖÊÁ¿m1=6ms£¬ÊÔͨ¹ý¹ÀËãÀ´ÅжϰµÐÇBÓпÉÄÜÊǺڶ´Âð£¿
(G=6.67¡Á10-11N¡¤m2/kg2£¬ms=2.0¡Á1030kg)
²é¿´´ð°¸ºÍ½âÎö>>
¿ÆÄ¿£º¸ßÖÐÎïÀí À´Ô´£º ÌâÐÍ£º
ÉñÆæµÄºÚ¶´Êǽü´úÒýÁ¦ÀíÂÛËùÔ¤ÑÔµÄÒ»ÖÖÌØÊâÌìÌ壬̽ѰºÚ¶´µÄ·½°¸Ö®Ò»Êǹ۲âË«ÐÇϵͳµÄÔ˶¯¹æÂÉ¡£ÌìÎÄѧ¼Ò¹Û²âºÓÍâÐÇϵÂóÕÜÂ×ÔÆʱ£¬·¢ÏÖÁËLMCX-3Ë«ÐÇϵͳ£¬ËüÓɿɼûÐÇAºÍ²»¿É¼ûµÄ°µÐÇB¹¹³É£¬Á½ÐÇÊÓΪÖʵ㣬²»¿¼ÂÇÆäËüÌìÌåµÄÓ°Ï죬A¡¢BΧÈÆÁ½ÕßµÄÁ¬ÏßÉϵÄOµã×öÔÈËÙÔ²ÖÜÔ˶¯£¬ËüÃÇÖ®¼äµÄ¾àÀë±£³Ö²»±ä£¬ÈçͼËùʾ£¬ÒýÁ¦³£Á¿ÎªG£¬Óɹ۲âÄܹ»µÃµ½¿É¼ûÐÇAµÄËÙÂÊvºÍÔËÐÐÖÜÆÚT¡£
£¨1£©¿É¼ûÐÇAËùÊÜ°µÐÇBµÄÒýÁ¦FA¿ÉµÈЧΪλÓÚOµã´¦ÖÊÁ¿Îªm£§µÄÐÇÌ壨ÊÓΪÖʵ㣩¶ÔËüµÄÒýÁ¦£¬ÉèAºÍBµÄÖÊÁ¿·Ö±ðΪm1¡¢m2¡£ÊÔÇóm£§£¨ÓÃm1¡¢m2±íʾ£©
£¨2£©Çó°µÐÇBµÄÖÊÁ¿m2Óë¿É¼ûÐÇAµÄËÙÂÊv¡¢ÔËÐÐÖÜÆÚTºÍÖÊÁ¿m1Ö®¼äµÄ¹Øϵʽ¡£
²é¿´´ð°¸ºÍ½âÎö>>
¿ÆÄ¿£º¸ßÖÐÎïÀí À´Ô´£º ÌâÐÍ£º
ÉñÆæµÄºÚ¶´Êǽü´úÒýÁ¦ÀíÂÛËùÔ¤ÑÔµÄÒ»ÖÖÌØÊâÌìÌ壬̽ѰºÚ¶´µÄ·½°¸Ö®Ò»Êǹ۲âË«ÐÇϵͳµÄÔ˶¯¹æÂÉ£®ÌìÎÄѧ¼Ò¹Û²âºÓÍâÐÇϵ´óÂóÕÜÂ×ÔÆʱ£¬·¢ÏÖÁËLMCX-3Ë«ÐÇϵͳ£¬ËüÓɿɼûÐÇAºÍ²»¿É¼ûµÄ°µÐÇB¹¹³É£®Á½ÐÇÊÓΪÖʵ㣬²»¿¼ÂÇÆäËüÐÇÌåµÄÓ°Ï죬A¡¢BΧÈÆÁ½ÕßÁ¬ÏßÉϵÄOµã×öÔÈËÙÔ²ÖÜÔ˶¯£¬ËüÃÇÖ®¼äµÄ¾àÀë±£³Ö²»±ä£¬Èçͼ18Ëùʾ£®ÒýÁ¦³£Á¿ÎªG£¬Óɹ۲âÄܹ»µÃµ½¿É¼ûÐÇAµÄËÙÂÊvºÍÔËÐÐÖÜÆÚT£®
£¨1£©¿É¼ûÐÇAËùÊÜ°µÐÇBµÄÒýÁ¦FA¿ÉµÈЧΪλÓÚOµã´¦ÖÊÁ¿ÎªµÄÐÇÌ壨¿ÉÊÓΪÖʵ㣩¶ÔËüµÄÒýÁ¦£¬ÉèAºÍBµÄÖÊÁ¿·Ö±ðΪm1¡¢m2£¬ÊÔÇó£¨ÓÃm1¡¢m2±íʾ£©£»
£¨2£©Çó°µÐÇBµÄµÄÖÊÁ¿m2Óë¿É¼ûÐÇAµÄËÙÂÊv¡¢ÔËÐÐÖÜÆÚTºÍÖÊÁ¿m1Ö®¼äµÄ¹Øϵʽ£»
£¨3£©ºãÐÇÑÝ»¯µ½Ä©ÆÚ£¬Èç¹ûÆäÖÊÁ¿´óÓÚÌ«ÑôÖÊÁ¿msµÄ2±¶£¬Ëü½«ÓпÉÄܳÉΪºÚ¶´£®Èô¿É¼ûÐÇAµÄËÙÂÊ£¬ÔËÐÐÖÜÆÚ£¬ÖÊÁ¿m1=6ms£¬ÊÔͨ¹ý¹ÀËãÀ´ÅжϰµÐÇBÓпÉÄÜÊǺڶ´Â𣿠ͼ18
£¨£¬£©
²é¿´´ð°¸ºÍ½âÎö>>
°Ù¶ÈÖÂÐÅ - Á·Ï°²áÁбí - ÊÔÌâÁбí
ºþ±±Ê¡»¥ÁªÍøÎ¥·¨ºÍ²»Á¼ÐÅÏ¢¾Ù±¨Æ½Ì¨ | ÍøÉÏÓк¦ÐÅÏ¢¾Ù±¨×¨Çø | µçÐÅթƾٱ¨×¨Çø | ÉæÀúÊ·ÐéÎÞÖ÷ÒåÓк¦ÐÅÏ¢¾Ù±¨×¨Çø | ÉæÆóÇÖȨ¾Ù±¨×¨Çø
Î¥·¨ºÍ²»Á¼ÐÅÏ¢¾Ù±¨µç»°£º027-86699610 ¾Ù±¨ÓÊÏ䣺58377363@163.com