Question

2£®ÈçͼËùʾ£¬µçÔ´µç¶¯ÊÆE₀=15V£¬ÄÚ×èr₀=1¦¸£¬µç×èR₁=30¦¸£¬R₂=60¦¸£®¼ä¾àd=0.2mµÄÁ½Æ½ÐнðÊô°åˮƽ·ÅÖ㬰å¼ä·Ö²¼Óд¹Ö±ÓÚÖ½ÃæÏòÀï¡¢´Å¸ÐӦǿ¶ÈB=1TµÄÔÈÇ¿´Å³¡£®±ÕºÏ¿ª¹ØS£¬°å¼äµç³¡ÊÓΪÔÈÇ¿µç³¡£¬½«Ò»´øÕýµçµÄСÇòÒÔ³õËÙ¶Èv=0.1m/sÑØÁ½°å¼äÖÐÏßˮƽÉäÈë°å¼ä£®É軬¶¯±ä×èÆ÷½ÓÈëµç·µÄ×èֵΪR_x£¬ºöÂÔ¿ÕÆø¶ÔСÇòµÄ×÷Óã®
£¨1£©µ±R_x=29¦¸Ê±£¬Á÷¹ýµçÔ´µÄ×ܵçÁ÷ÊǶàÉÙ£¿
£¨2£©µ±R_x=29¦¸Ê±£¬µç×èR₂ÏûºÄµÄµç¹¦ÂÊÊǶà´ó£¿
£¨3£©ÈôСÇò½øÈë°å¼ä×öÔÈËÙÔ²ÖÜÔ˶¯²¢Ó뼫°åÏàÅö£¬ÅöʱËÙ¶ÈÓë³õËٶȵļнÇΪ60¡ã£¬ÔòСÇòÓëÄĸö¼«°åÏàÅö£¬´ËʱR_xÊǶàÉÙ£¿

Answer 1

·ÖÎö £¨1£©Óɵç·ͼ¿ÉÖª£¬R₁ÓëR₂²¢ÁªºóÓ뻬¶¯±ä×èÆ÷´®Áª£¬ÓÉ´®²¢Áªµç·µÄÐÔÖʿɵóö×ܵç×裬Óɱպϵç·ŷķ¶¨Âɿɵõç·ÖеĵçÁ÷
£¨2£©ÏÈÇó³öR₂Á½¶ËµÄµçѹ£¬ÔÙÓɹ¦Âʹ«Ê½P=$\frac{{U}_{\;}^{2}}{R}$¿ÉÇóµÃR₂ÏûºÄµÄµç¹¦ÂÊ£»
£¨3£©Á£×Ó½øÈë°å¼äºó×öÔÈËÙÔ²ÖÜÔ˶¯£¬µç³¡Á¦ÓëÖØÁ¦Æ½ºâ£¬¸ù¾ÝÂåÂ××ÈÁ¦ÌṩÏòÐÄÁ¦£¬µÃµ½µçÈÝÆ÷µÄµçѹ£»Óɱպϵç·ŷķ¶¨ÂÉ¿ÉÇóµÃ»¬¶¯±ä×èÆ÷µÄ×èÖµ£®

½â´ð ½â£º£¨1£©±ÕºÏµç·µÄÍâµç×èΪ£º
$R={R}_{x}^{\;}+\frac{{R}_{1}^{\;}{R}_{2}^{\;}}{{R}_{1}^{\;}+{R}_{2}^{\;}}=49¦¸$
¸ù¾Ý±ÕºÏµç·µÄÅ·Ä·¶¨ÂÉ
$I=\frac{E}{R+r}=0.3A$
£¨2£©${R}_{2}^{\;}$Á½¶ËµÄµçѹΪ
${U}_{2}^{\;}=E-I£¨{R}_{x}^{\;}+r£©=6V$
${R}_{2}^{\;}$ÏûºÄµÄ¹¦ÂÊΪ
${P}_{2}^{\;}=\frac{{U}_{2}^{2}}{{R}_{2}^{\;}}=0.6W$
£¨3£©Ð¡Çò½øÈëµç´Å³¡×öÔÈËÙÔ²ÖÜÔ˶¯£¬ËµÃ÷ÖØÁ¦ºÍµç³¡Á¦µÈ´ó·´Ïò£¬ÂåÂ××ÈÁ¦ÌṩÏòÐÄÁ¦£¬Ð¡ÇòÏòÉÏÆ«´òÔÚÉϼ«°å
СÇò×öÔÈËÙÔ²ÖÜÔ˶¯µÄ³õÄ©ËٵļнǵÈÓÚÔ²ÐĽÇ60¡ã£¬¸ù¾Ý¼¸ºÎ¹ØϵµÃ
r=d
$qvB=m\frac{{v}_{\;}^{2}}{r}$
$mg=q\frac{{U}_{2}^{\;}}{d}$
µÃ${U}_{2}^{\;}=\frac{B{d}_{\;}^{2}g}{v}=4V$
¸É·µçÁ÷Ϊ$I=\frac{{U}_{2}^{\;}}{{R}_{12}^{\;}}=0.2A$
${R}_{x}^{\;}=\frac{E-{U}_{2}^{\;}}{I}-r=54¦¸$
´ð£º£¨1£©µ±R_x=29¦¸Ê±£¬Á÷¹ýµçÔ´µÄ×ܵçÁ÷ÊÇ0.3A
£¨2£©µ±R_x=29¦¸Ê±£¬µç×èR₂ÏûºÄµÄµç¹¦ÂÊÊÇ0.6W
£¨3£©ÈôСÇò½øÈë°å¼ä×öÔÈËÙÔ²ÖÜÔ˶¯²¢Ó뼫°åÏàÅö£¬ÅöʱËÙ¶ÈÓë³õËٶȵļнÇΪ60¡ã£¬ÔòСÇòÓëÄĸö¼«°åÏàÅö£¬´ËʱR_xÊÇ54¦¸

µãÆÀ ±¾ÌâΪ´øµçÁ£×ÓÔÚ¸´ºÏ³¡ÖеÄÔ˶¯Óë±ÕºÏµç·ŷķ¶¨ÂɵÄ×ÛºÏÐÔÌâÄ¿£¬½âÌâµÄ¹Ø¼üÔÚÓÚÃ÷È·´øµçÁ£×ÓÔÚ¸´ºÏ³¡ÖÐ×öÔÈËÙÔ²ÖÜÔ˶¯Ê±£¬ËùÊܵ½µÄµç³¡Á¦Ò»¶¨ÓëÖØÁ¦Æ½ºâ£»²»ÄÑ£®