14£®Èçͼ£¬Ïä×ÓAÁ¬Í¬¹Ì¶¨ÔÚÏä×ӵײ¿µÄÊúÖ±¸ËµÄ×ÜÖÊÁ¿ÎªM=10kg£®Ïä×ÓÄÚ²¿¸ß¶ÈH=3.75m£¬¸Ë³¤h=2.5m£¬ÁíÓÐÒ»ÖÊÁ¿Îªm=2kgµÄСÌú»·BÌ×ÔÚ¸ËÉÏ£¬´Ó¸ËµÄµ×²¿ÒÔv0=10m/sµÄ³õËٶȿªÊ¼ÏòÉÏÔ˶¯£¬Ìú»·B¸ÕºÃÄܵ½´ïÏ䶥£¬²»¼Æ¿ÕÆø×èÁ¦£¬gÈ¡10m/s2£®Çó£º
£¨1£©ÔÚÌú»·ÑØןËÏòÉÏ»¬µÄ¹ý³ÌÖУ¬ËùÊܵ½µÄĦ²ÁÁ¦´óСΪ¶àÉÙ£¿
£¨2£©Ð¡Ìú»·´Ó¿ªÊ¼Ô˶¯ºó¾­¶à³¤Ê±¼ä´ïµ½Ï䶥£®

·ÖÎö ¸ù¾ÝËÙ¶ÈλÒƹ«Ê½Çó³öÌú»·ÍÑÀë¸Ë×ÓµÄËٶȣ¬´Ó¶ø¸ù¾ÝËÙ¶ÈλÒƹ«Ê½Çó³öÔÚ¸Ë×ÓÉÏ×öÔȼõËÙÔ˶¯µÄ¼ÓËٶȴóС£¬½áºÏÅ£¶ÙµÚ¶þ¶¨ÂÉÇó³öĦ²ÁÁ¦µÄ´óС£®
¸ù¾ÝËÙ¶Èʱ¼ä¹«Ê½·Ö±ðÇó³öÔÚ¸Ë×ÓÉϺÍÍÑÀë¸Ë×ÓºóµÄÔ˶¯Ê±¼ä£¬´Ó¶øµÃ³ö×Üʱ¼ä£®

½â´ð ½â£º£¨1£©ÓÉÓÚÌú»·B¸ÕºÃÄܵ½´ïÏ䶥£¬¼´µ½´ïÏ䶥µÄËÙ¶ÈΪÁ㣬ÉèÌú»·Ô˶¯µ½¸Ë¶¥µÄËÙ¶ÈΪv£¬ÔòÓУº
v2=2g£¨H-h£©£¬
½âµÃ£ºv=$\sqrt{2g£¨H-h£©}=\sqrt{2¡Á10¡Á£¨3.75-2.5£©}$m/s=5m/s£®
¸ù¾Ý${{v}_{0}}^{2}-{v}^{2}=2ah$µÃÔÚ¸ËÉÏÔȼõËÙÔ˶¯µÄ¼ÓËٶȴóСΪ£º
a=$\frac{{{v}_{0}}^{2}-{v}^{2}}{2h}=\frac{100-25}{5}m/{s}^{2}=15m/{s}^{2}$£¬
¸ù¾ÝÅ£¶ÙµÚ¶þ¶¨Âɵãºmg+f=ma£¬
½âµÃ£ºf=ma-mg=2¡Á£¨15-10£©N=10N£®
£¨2£©ÔÚ¸ËÉϵÄÔ˶¯Ê±¼äΪ£º${t}_{1}=\frac{{v}_{0}-v}{a}=\frac{10-5}{15}s=\frac{1}{3}s$£¬
À뿪¸Ë×ÓºóµÄÔ˶¯Ê±¼äΪ£º${t}_{2}=\frac{v}{g}=\frac{5}{10}s=\frac{1}{2}s$£¬
ÔòÓУºt=${t}_{1}+{t}_{2}=\frac{1}{3}+\frac{1}{2}s=\frac{5}{6}s$£®
´ð£º£¨1£©ÔÚÌú»·ÑØןËÏòÉÏ»¬µÄ¹ý³ÌÖУ¬ËùÊܵ½µÄĦ²ÁÁ¦´óСΪ10N£»
£¨2£©Ð¡Ìú»·´Ó¿ªÊ¼Ô˶¯ºó¾­$\frac{5}{6}s$ʱ¼ä´ïµ½Ï䶥£®

µãÆÀ ±¾Ì⿼²éÁËÅ£¶ÙµÚ¶þ¶¨ÂɺÍÔ˶¯Ñ§¹«Ê½µÄ»ù±¾ÔËÓã¬ÖªµÀ¼ÓËÙ¶ÈÊÇÁªÏµÁ¦Ñ§ºÍÔ˶¯Ñ§µÄÇÅÁº£¬±¾Ìâͨ¹ýËÙ¶ÈλÒƹ«Ê½Çó³öÍÑÀë¸ËµÄËٶȺÍÔÚ¸ËÉϵļÓËٶȴóСÊǹؼü£®

Á·Ï°²áϵÁдð°¸
Ïà¹ØÏ°Ìâ

¿ÆÄ¿£º¸ßÖÐÎïÀí À´Ô´£º ÌâÐÍ£ºÑ¡ÔñÌâ

4£®Èçͼ¼×Ëùʾ£¬Ô²ÐÎÏßȦMµÄÔÑÊýΪ50ÔÑ£¬ËüµÄÁ½¸ö¶Ëµãa¡¢bÓëÀíÏëµçѹ±íÏàÁ¬£¬ÏßȦÖдų¡·½ÏòÈçͼ£¬ÏßȦÖдÅͨÁ¿µÄ±ä»¯¹æÂÉÈçͼÒÒËùʾ£¬ÔòabÁ½µãµÄµçÊƸߵÍÓëµçѹ±í¶ÁÊýΪ£¨¡¡¡¡£©
A£®¦Õa£¾¦Õb£¬20VB£®¦Õa£¾¦Õb£¬10VC£®¦Õa£¼¦Õb£¬20VD£®¦Õa£¼¦Õb£¬10V

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖÐÎïÀí À´Ô´£º ÌâÐÍ£ºÑ¡ÔñÌâ

5£®ÈçͼËùʾ£¬ÔÚÔÈÇ¿´Å³¡ÖзÅÓÐƽÐÐÍ­µ¼¹ì£¬ËüÓë´óÏßȦMÏàÁ¬£¬ÒªÊ¹µ¼ÏßȦN»ñµÃ˳ʱÕë·½ÏòµÄ¸ÐÓ¦µçÁ÷£¬²¢ÇÒNÏßȦÃæ»ýÓÐÓÐÊÕËõµÄÇ÷ÊÆ£®Ôò·ÅÔÚµ¼¹ìÉϵÄÂã½ðÊô°ôabµÄÔ˶¯Çé¿öÊÇ£¨Á½ÏßȦ¹²Ãæ·ÅÖã©£¨¡¡¡¡£©
A£®ÏòÓÒÔÈËÙÔ˶¯B£®Ïò×ó¼ÓËÙÔ˶¯C£®ÏòÓÒ¼õËÙÔ˶¯D£®ÏòÓÒ¼ÓËÙÔ˶¯

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖÐÎïÀí À´Ô´£º ÌâÐÍ£º½â´ðÌâ

2£®¿ªÆÕÀÕÈý´ó¶¨Âɵķ¢ÏÖΪÈËÀà¶ÔÌìÌåÔ˶¯¹æÂɵÄÈÏʶ×÷³ö¾Þ´ó¹±Ï×£®ÆäÖпªÆÕÀÕµÚÈý¶¨ÂɸæËßÎÒÃÇ£ºÐÐÐÇÈÆÌ«ÑôÒ»ÖÜËùÐèʱ¼äµÄƽ·½¸úÆäÍÖÔ²¹ìµÀ°ë³¤ÖáµÄÁ¢·½Ö®±ÈÊÇÒ»¸ö³£Êý£®
ÐÐÐÇË®ÐǽðÐǵØÇò»ðÐÇľÐÇÍÁÐÇ
¹ìµÀ°ë¾¶£¨¡Á107Km£©5.810.81522.877.8147.8
Èç±í±íʾ̫ÑôϵÖÐijЩÐÐÐÇÈÆÌ«ÑôÔËÐеĹìµÀ°ë¾¶£¬Éè¸÷ÐÐÐÇÈÆÌ«Ñô×öÔ²ÖÜÔ˶¯£¬¹ìµÀ°ë³¤ÖáµÈÓÚ¹ìµÀ°ë¾¶£®Çë¼ÆËã³öË®ÐÇÈÆÌ«Ñô¹«×ªµÄÖÜÆÚ£¿

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖÐÎïÀí À´Ô´£º ÌâÐÍ£ºÑ¡ÔñÌâ

9£®ÏÂÁйØÓÚÕñ¶¯µÄ˵·¨ÕýÈ·µÄÊÇ£¨¡¡¡¡£©
A£®ÓÃÖØ´¸Çû÷Ò»ÏÂÐüµõ×ŵÄÖÓºó£¬Öӵİڶ¯ÊôÓÚÊÜÆÈÕñ¶¯
B£®´òµã¼ÆʱÆ÷½ÓͨµçÔ´ºó£¬ÕñÕëµÄÕñ¶¯ÊôÓÚ×ÔÓÉÕñ¶¯
C£®ºöÂÔ¿ÕÆø×èÁ¦£¬µ¯»ÉÕñ×ÓÔÚÊúÖ±·½ÏòÉÏÑØÉÏÏ·½ÏòÕñ¶¯ÊôÓÚ¼òгÕñ¶¯
D£®·ÀÖ¹¹²ÕñΣº¦Ê±£¬Ó¦Ê¹Çý¶¯Á¦µÄƵÂʽӽü»òµÈÓÚÕñ¶¯ÎïÌåµÄ¹ÌÓÐƵÂÊ£»ÀûÓù²Õñʱ£¬Ó¦Ê¹Çý¶¯Á¦µÄƵÂÊÔ¶ÀëÕñ¶¯ÎïÌåµÄ¹ÌÓÐƵÂÊ

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖÐÎïÀí À´Ô´£º ÌâÐÍ£º½â´ðÌâ

19£®ÔÚÀûÓõçÁ÷±íºÍµç×èÏä²â¶¨µçÔ´µç¶¯ÊƺÍÄÚµç×èµÄʵÑéÖУ¬µçÁ÷±íµÄÄÚ×èºÜС¿ÉÊÓΪÀíÏëµç±í£¬µç·Èçͼ1Ëùʾ£¬Á¬½ÓºÃµç·²¢½øÐÐÈçϲÙ×÷£º±ÕºÏ¿ª¹ØS£¬µ÷½Úµç×èÏäµÄ×èÖµ£¬²¢¼Ç¼ÏÂÿ´Îµç×èÏäµÄ×èÖµR¼°¶ÔÓ¦µÄµçÁ÷±íAʾÊýI£»

£¨1£©ÈôʵÑéÖУ¬Ä³Í¬Ñ§½ö²âÁ¿»ñµÃÁ½×éÊý¾Ý£ºµ±µçÁ÷±í¶ÁÊýΪI1ʱ£¬µç×èÏä¶ÁÊýΪR1£»µ±µçÁ÷±í¶ÁÊýΪI2ʱ£¬µç×èÏä¶ÁÊýΪR2£®ÔòµçÔ´µç¶¯ÊÆEºÍÄÚ×èr¿ÉÓÃËù²âµÄÎïÀíÁ¿I1¡¢I2¡¢R1¡¢R2±íʾΪE=$\frac{{I}_{1}{I}_{2}£¨{R}_{1}-{R}_{2}£©}{{I}_{2}-{I}_{1}}$£¬r=$\frac{{I}_{1}{R}_{1}-{I}_{2}{R}_{2}}{{I}_{2}-{I}_{1}}$£®
£¨2£©ÈôÁíһͬѧ²âµÃ10×éI¡¢RµÄÊý¾Ý£¬²¢×÷³öÁËÈçͼ2ÖÐaËùʾµÄͼÏó£¬Ôò¸ù¾ÝͼÏó¿ÉÇó³öE=2.0V£¬r=2.0¦¸£®
£¨3£©ÒÑ֪ijµç×èÔª¼þR1µÄ$\frac{1}{I}$-RͼÏóÈçͼ2ÖÐbËùʾ£¬ÈôÓÃʵÑéµÄµçÔ´¸ø´ËÔª¼þ¹©µç£¬´ËÔª¼þµÄÈȹ¦ÂÊΪ0.375W£®

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖÐÎïÀí À´Ô´£º ÌâÐÍ£ºÑ¡ÔñÌâ

6£®ÈçͼËùʾ£¬50ÔѾØÐαպϵ¼Ïß¿òABCD´¦ÓڴŸÐӦǿ¶È´óСB=$\frac{\sqrt{2}}{10}$TµÄˮƽÔÈÇ¿´Å³¡ÖУ¬Ïß¿òÃæ»ýS=0.5m2£¬Ïß¿òµç×è²»¼Æ£¬Ïß¿òÈÆ´¹Ö±Óڴų¡µÄÖáOO¡äÒÔ½ÇËٶȦØ=200rad/sÔÈËÙת¶¯£¬²¢ÓëÀíÏë±äѹÆ÷Ô­ÏßȦÏàÁ¬£¬¸±ÏßȦ½ÓÈëÒÑÒ»Ö»¡°220V 60W¡±µÆÅÝ£¬ÇÒµÆÅÝÕý³£·¢¹â£¬ÈÛ¶ÏÆ÷ÔÊÐíͨ¹ýµÄ×î´óµç·Ϊ10A£¬ÏÂÁÐ˵·¨ÕýÈ·µÄÊÇ£¨¡¡¡¡£©
A£®Í¼Ê¾Î»Öô©¹ýÏß¿òµÄ´ÅͨÁ¿±ä»¯Âʲ»ÎªÁã
B£®Èô´ÓͼʾλÖÿªÊ¼¼Æʱ£¬Ïß¿òÖвúÉú½»±äµçµÄ±í´ïʽΪe=250$\sqrt{2}$sin£¨200t£©V
C£®±äѹÆ÷Ô­¡¢¸±ÏßȦÔÑÊýÖ®±ÈΪ50£º11
D£®ÔÊÐí±äѹÆ÷Êä³öµÄ×î´ó¹¦ÂÊΪ5000W

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖÐÎïÀí À´Ô´£º ÌâÐÍ£º½â´ðÌâ

3£®Èçͼ£¬ÊÇÃèÊöÒ»¶¨ÖÊÁ¿µÄÀíÏëÆøÌåѹǿpÓëÈÈÁ¦Ñ§Î¶ÈTµÄ±ä»¯¹ØϵͼÏó£¬ÒÑÖªÆøÌåÔÚ״̬AʱµÄÌå»ýv0=1m3£¬Ï߶ÎABÓëPÖáƽÐУ»ÇÒÆøÌå´Ó״̬A±ä»¯µ½×´Ì¬B¹ý³ÌÖУ¬ÏòÍâ½ç·Å³öÁË30JÈÈÁ¿£¬Çó£º
£¨1£©ÆøÌåÔÚ״̬BʱµÄÌå»ý£»
£¨2£©ÆøÌå´Ó״̬A±ä»¯µ½×´Ì¬B¹ý³ÌÖУ¬Íâ½ç¶ÔÆøÌå×öÁ˶àÉÙ¹¦£¿

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖÐÎïÀí À´Ô´£º ÌâÐÍ£ºÑ¡ÔñÌâ

4£®Ò»ÀíÏë±äѹÆ÷¸ø¸ºÔع©µç£¬±äѹÆ÷ÊäÈëµçѹ²»±ä£¬ÈçͼËùʾ£®Èç¹û¸ºÔصç×èµÄ»¬¶¯Æ¬ÏòÉÏÒƶ¯£¬ÔòͼÖÐËùÓн»Á÷µç±íµÄ¶ÁÊý¼°ÊäÈ빦Âʱ仯Çé¿öÕýÈ·µÄÊÇ£¨¾ùΪÀíÏëµç±í£©£¨¡¡¡¡£©
A£®V1¡¢V2²»±ä£¬A1Ôö´ó£¬A2¼õС£¬PÔö´ó
B£®V1¡¢V2²»±ä£¬A1¡¢A2Ôö´ó£¬PÔö´ó
C£®V1¡¢V2²»±ä£¬A1¡¢A2¼õС£¬P¼õС
D£®V1²»±ä£¬V2Ôö´ó£¬A1¼õС£¬A2¼õС£¬P¼õС

²é¿´´ð°¸ºÍ½âÎö>>

ͬ²½Á·Ï°²á´ð°¸