ÈçͼËùʾ£¬Á½Æ½ÐнðÊô°åA¡¢B³¤l£½8cm£¬Á½°å¼ä¾àÀëd£½8cm£¬A°å±ÈB°åµçÊƸß300V£¬¼´UAB£½300V£®Ò»´øÕýµçµÄÁ£×ÓµçÁ¿q£½10-10C£¬ÖÊÁ¿m£½10-20kg£¬´ÓRµãÑص糡ÖÐÐÄÏß´¹Ö±µç³¡Ïß·ÉÈëµç³¡£¬³õËÙ¶Èv0£½2¡Á106m/s£¬Á£×ӷɳöƽÐаåµç³¡ºó¾­¹ý½çÃæMN¡¢PS¼äµÄÎ޵糡ÇøÓòºó£¬½øÈë¹Ì¶¨ÔÚÖÐÐÄÏßÉÏOµãµÄµãµçºÉQÐγɵĵ糡ÇøÓò£¨Éè½çÃæPSÓұߵãµçºÉµÄµç³¡·Ö²¼²»ÊܽçÃæµÄÓ°Ï죩£®ÒÑÖªÁ½½çÃæMN¡¢PSÏà¾àΪL£½12cm£¬Á£×Ó´©¹ý½çÃæPS×îºó´¹Ö±´òÔÚ·ÅÖÃÓÚÖÐÐÄÏßÉϵÄÓ«¹âÆÁEFÉÏ£®£¨¾²µçÁ¦³£Êýk£½9¡Á109N??m2/C2£©Çó

£¨1£©Á£×Ó´©¹ý½çÃæMNʱµÄËٶȣ»

£¨2£©Á£×Ó´©¹ý½çÃæPSʱƫÀëÖÐÐÄÏßROµÄ¾àÀë¶àÔ¶£»

£¨3£©µãµçºÉµÄµçÁ¿£®

£¨1£©2.5¡Á106£¨m/s£©    

       £¨2£©12cm     

        (3) 1.04¡Á10-8£¨C£©  


½âÎö:

½â£º£¨1£©Á£×ÓÔÚƽ°åµçÈÝÆ÷ÖзÉÐеÄʱ¼ä£ºt==4¡Á10-8(s)      £¨1·Ö£©

    ÔòÁ£×ӷɳöµçÈÝÆ÷ʱÑص糡·½ÏòµÄËٶȣºvy=1.5¡Á106£¨m/s£©      £¨1·Ö£©

ÔòÁ£×Ó´©¹ý½çÃæMNʱµÄËٶȣºv=          £¨1·Ö£©

=2.5¡Á106£¨m/s£©      £¨1·Ö£©

     £¨2£©Á£×Ó´©¹ý½çÃæMNʱµÄ²àÒÆÁ¿£ºy1=t=3(cm)      £¨1·Ö£©

             Ôò´©¹ý½çÃæPSʱƫÀëÖÐÐÄÏߵľàÀëÓÉÏàËÆÈý½ÇÐεã¨Èçͼ£©

              ==4      £¨2·Ö£© 

y2=12cm      £¨1·Ö£©

          (3)ÓÉÌ⣬Á£×ÓÔÚPSÓÒ±ßÇøÓò×öÔÈËÙÔ²ÖÜÔ˶¯£¬°ë¾¶

R= =15(cm)      £¨2·Ö£©

             ÇÒK=m        £¨2·Ö£©        

Q=¡Ö1.04¡Á10-8£¨C£©      £¨1·Ö£©

                 

Á·Ï°²áϵÁдð°¸
Ïà¹ØÏ°Ìâ

¿ÆÄ¿£º¸ßÖÐÎïÀí À´Ô´£º ÌâÐÍ£º

ÈçͼËùʾ£¬Á½Æ½ÐнðÊô°å¼äÓÐÒ»ÔÈÇ¿µç³¡£¬°å³¤ÎªL£¬°å¼ä¾àÀëΪd£¬ÔÚ °åÓÒ¶ËL´¦ÓÐÒ»ÊúÖ±·ÅÖõĹâÆÁM£¬Ò»´øµçºÉÁ¿Îªq£¬ÖÊÁ¿ÎªmµÄÖʵã´ÓÁ½°åÖÐÑëÉäÈë°å¼ä£¬×îºó´¹Ö±´òÔÚMÆÁÉÏ£¬ÔòÏÂÁнáÂÛÕýÈ·µÄÊÇ£¨¡¡¡¡£©

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖÐÎïÀí À´Ô´£º ÌâÐÍ£º

ÈçͼËùʾ£¬Á½Æ½ÐнðÊô°åÖÐÓÐÏ໥´¹Ö±µÄÔÈÇ¿µç³¡ºÍÔÈÇ¿´Å³¡£¬´øÕýµçµÄÁ£×Ó£¨²»¼ÆÁ£×ÓµÄÖØÁ¦£©´ÓÁ½°åÖÐÑë´¹Ö±µç³¡¡¢´Å³¡ÈëÉ䣮ËüÔÚ½ðÊô°å¼äÔ˶¯µÄ¹ì¼£ÎªË®Æ½Ö±Ïߣ¬ÈçͼÖÐÐéÏßËùʾ£®ÈôʹÁ£×Ó·ÉÔ½½ðÊô°å¼äµÄ¹ý³ÌÖÐÏòÉÏ°åÆ«ÒÆ£¬Ôò¿ÉÒÔ²ÉÈ¡ÏÂÁеÄÕýÈ·´ëʩΪ£¨¡¡¡¡£©

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖÐÎïÀí À´Ô´£º ÌâÐÍ£º

ÈçͼËùʾ£¬Á½Æ½ÐнðÊô°åµÄ¼ä¾àµÈÓÚ¼«°åµÄ³¤¶È£¬ÏÖÓÐÖØÁ¦²»¼ÆµÄÕýÀë×ÓÊøÒÔÏàͬµÄ³õËÙ¶Èv0ƽÐÐÓÚÁ½°å´ÓÁ½°åÕýÖмäÉäÈ룮µÚÒ»´ÎÔÚÁ½¼«°å¼ä¼Óºã¶¨µçѹ£¬½¨Á¢³¡Ç¿ÎªEµÄÔÈÇ¿µç³¡£¬ÔòÕýÀë×ÓÊø¸ÕºÃ´ÓÉϼ«°å±ßÔµ·É³ö£®µÚ¶þ´Î³·È¥µç³¡£¬ÔÚÁ½°å¼ä½¨Á¢´Å¸ÐӦǿ¶ÈΪB¡¢·½Ïò´¹Ö±ÓÚÖ½ÃæµÄÔÈÇ¿´Å³¡£¬ÕýÀë×ÓÊø¸ÕºÃ´Óϼ«°å±ßÔµ·É³ö£¬ÔòEºÍBµÄ´óС֮±ÈΪ£¨¡¡¡¡£©

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖÐÎïÀí À´Ô´£º ÌâÐÍ£º

ÈçͼËùʾ£¬Á½Æ½ÐнðÊô°å¼äµç³¡ÊÇÔÈÇ¿µç³¡£¬³¡Ç¿´óСΪ1.0¡Á104V/m£¬A¡¢BÁ½°åÏà¾à1cm£¬CµãÓëAÏà¾à0.4cm£¬ÈôB½ÓµØ£¬ÔòA¡¢C¼äµçÊƲîUAC=
40V
40V
£¬½«´øµçÁ¿Îª-1.0¡Á10-12CµÄµãµçºÉÖÃÓÚCµã£¬ÆäµçÊÆÄÜΪ
-6¡Á10-11J
-6¡Á10-11J
£®

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖÐÎïÀí À´Ô´£º ÌâÐÍ£º

¾«Ó¢¼Ò½ÌÍøÈçͼËùʾ£¬Á½Æ½ÐнðÊô°åˮƽ·ÅÖ㬿ªÊ¼¿ª¹ØSºÏÉÏʹƽÐаåµçÈÝÆ÷´øµç£®°å¼ä´æÔÚ´¹Ö±Ö½ÃæÏòÀïµÄÔÈÇ¿´Å³¡£®Ò»¸ö²»¼ÆÖØÁ¦µÄ´øµçÁ£×ÓÇ¡ÄÜÒÔˮƽÏòÓÒµÄËÙ¶ÈÑØÖ±Ïßͨ¹ýÁ½°å£®ÔÚÒÔÏ·½·¨ÖУ¬ÄÜʹ´øµçÁ£×ÓÈÔÑØˮƽֱÏßͨ¹ýÁ½°åµÄÊÇ£¨¡¡¡¡£©
A¡¢°ÑÁ½°å¼ä¾àÀë¼õСһ°ë£¬Í¬Ê±°ÑÁ£×ÓËÙÂÊÔö¼ÓÒ»±¶B¡¢°ÑÁ½°åµÄ¾àÀëÔö´óÒ»±¶£¬Í¬Ê±°Ñ°å¼äµÄ´Å¸ÐӦǿ¶ÈÔö´óÒ»±¶C¡¢°Ñ¿ª¹ØS¶Ï¿ª£¬Á½°åµÄ¾àÀëÔö´óÒ»±¶£¬Í¬Ê±°Ñ°å¼äµÄ´Å¸ÐӦǿ¶È¼õΪһ°ëD¡¢°Ñ¿ª¹ØS¶Ï¿ª£¬Á½°åµÄ¾àÀë¼õСһ°ë£¬Í¬Ê±°ÑÁ£×ÓËÙÂʼõСһ°ë

²é¿´´ð°¸ºÍ½âÎö>>

ͬ²½Á·Ï°²á´ð°¸