5£®¸ßËÙ¶¯³µ×éÆô¶¯Ê±£¬ËùÓгµÂÖ¶¼ÄÜһͬÔËת£¬Ê¹µÃ¸÷³µÏáͬʱÆô¶¯£¬¶ø´«Í³ÁгµÒòΪ¸÷³µÏá¼ä´æÔÚһС¶Î¼ä϶£¬ËùÒÔ´Ó³µÍ·Æô¶¯µ½³µÎ²Æô¶¯ÓÐÒ»¸ö¹ý³Ì£¬Ôì³É»ú³µÇ£ÒýÁ¦Ëù×öµÄ¹¦ÓÐËðºÄ£¬Îª±ãÓڱȽϣ¬¼Ù¶¨¸ß¶È¶¯³µ×éºÍ´«Í³Áгµ¾ùÓÉn£¨n£¾2£©½Ú³µÏᣨÈÏΪ³µÍ·ÎªµÚ1½Ú³µÏᣩ¹¹³É£¬Ã¿½Ú³µÏáµÄÖÊÁ¿¾ùΪm£¬µ«´«Í³Áгµ¸÷³µÏá¼äµÄ¼ä϶Ϊd£¨ÈçͼËùʾ£¬Æô¶¯ºóÇ°ÃæµÄ³µÏáÔ˶¯¾àÀëdºó´ø¶¯ºóÒ»½Ú³µÏᣩ£¬ËüÃǶ¼ÔÚÏàͬ´óСΪFµÄºã¶¨Ç£ÒýÁ¦µÄ×÷ÓÃÏÂÆô¶¯£¬Ò»ÇÐ×èÁ¦²»¼Æ£¬´«Í³ÁгµÇ°Ò»³µÏá´ø¶¯ºóÒÔ³µÏáÔ˶¯Ê±ÊÓΪÍêÈ«·Çµ¯ÐÔÅöײ£¬Çó£º

£¨1£©´«Í³ÁгµµÚ1½Ú³µÏáÓëµÚ2½Ú³µÏáÅöײºó˲¼ä£¬µÚ2½Ú³µÏáµÄËٶȴóСv2£»
£¨2£©´«Í³ÁгµËùÓгµÏᶼ¿ªÊ¼Ô˶¯Ê±µÄ×ܶ¯ÄÜEk£»
£¨3£©¸ßËÙ¶¯³µ×éÔÚÁ¦FµÄ×÷ÓÃÏÂÓɾ²Ö¹¿ªÊ¼Í¨¹ýÓ봫ͳÁгµÆô¶¯¹ý³Ì£¨´ÓÆô¶¯µ½ËùÓгµÏᶼ¿ªÊ¼Ô˶¯£©Ïàͬ¾àÀëʱµÄ¶¯ÄÜEk'ÒÔ¼°$\frac{{{E_k}'}}{E_k}$£®

·ÖÎö £¨1£©Óɶ¯Äܶ¨ÀíÇó½â³ö³µÍ·£¨µÚÒ»½Ú³µÏᣩ´ø¶¯µÚ2½Ú³µÏáÇ°µÄËÙ˲ʱËٶȣ¬¸ù¾Ý¶¯Á¿Êغ㶨ÂÉ¿ÉÇó½â³öÁгµµÚ1½Ú³µÏá´ø¶¯µÚ2½Ú³µÏáºó˲¼äËٶȵĴóС
£¨2£©Óɶ¯Äܶ¨ÀíºÍ¶¯Á¿Êغ㶨ÂÉÇó½â³öµÚ¶þ½Ú³µÏá´ø¶¯µÚÈý½Ú³µÏáºóµÄ˲ʱËٶȴóС£¬ÕÒ³öµÄ¹æÂÉ£¬¼ÆËã³ö×ܶ¯ÄÜ
£¨3£©Óɶ¯Äܶ¨Àí¼ÆËã³ö¸ßËÙ¶¯³µµÄ¶¯ÄÜ

½â´ð ½â£º£¨1£©É贫ͳÁгµ³µÍ·£¨µÚ1½Ú³µÏᣩ´ø¶¯µÚ2½Ú³µÏáǰ˲¼äµÄËٶȴóСΪv1£¬Óɶ¯Äܶ¨ÀíÓУº$Fd=\frac{1}{2}mv_1^2-0$
É賵ͷ£¨µÚ1½Ú³µÏᣩ´ø¶¯µÚ2½Ú³µÏáºóµÄ˲ʱËÙ¶ÈΪv2£¬ÔÚ³µÍ·£¨µÚ1½Ú³µÏᣩ´ø¶¯µÚ2½Ú³µÏáÔ˶¯µÄ¹ý³ÌÖÐÓɶ¯Á¿Êغ㶨ÂÉÓУºmv1=2mv2£¬½âµÃv2=$\sqrt{\frac{Fd}{2m}}$
£¨2£©É贫ͳÁгµµÚ2½Ú³µÏá´ø¶¯µÚ3½Ú³µÏáÇ°µÄ˲ʱËÙ¶ÈΪv2¡ä£¬Óɶ¯Äܶ¨ÀíÓУºFd=$\frac{1}{2}$mv2/2-$\frac{1}{2}$mv22
ÉèµÚ¶þ½Ú³µÏá´ø¶¯µÚÈý½Ú³µÏáºóµÄ˲ʱËÙ¶ÈΪv3£¬Óɶ¯Á¿Êغ㶨ÂÉÓУº
2mv2¡ä=3mv3
½âµÃ£ºv3=$\sqrt{\frac{2Fd}{3m}}$
ÉèÅöײºó˲¼ä´«Í³ÁгµµÚ£¨n-1£©½Ú³µÏáµÄËٶȴóС${v_{n-1}}=\sqrt{\frac{{£¨{n-2}£©Fd}}{£¨n-1£©m}}$£¬µÚ£¨n-1£©½Ú³µÏá´ø¶¯µÚn½Ú³µÏáǰ˲¼äµÄËٶȴóСΪvn-1'£¬Óɶ¯Äܶ¨ÀíÓУº$Fd=\frac{1}{2}£¨n-1£©mv_{n-1}^{'2}-\frac{1}{2}£¨n-1£©mv_{n-1}^2$
ÉèÅöײȫ²¿Íê³É˲¼äËùÓгµÏáµÄËٶȴóСΪvn£¬Óɶ¯Á¿Êغ㶨ÂÉÓУº£¨n-1£©mvn-1'=nmvn
½âµÃ${v_n}=\sqrt{\frac{£¨n-1£©Fd}{nm}}$£¬¿ÉÖª¼ÙÉè³ÉÁ¢
¹Ê£¬${E_k}=\frac{1}{2}¡Ánmv_n^2$£¬½âµÃ${E_k}=\frac{£¨n-1£©Fd}{2}$
£¨3£©¾­·ÖÎö¿ÉÖª£¬´«Í³Áгµ´ÓÆô¶¯µ½ËùÓгµÏá¾ùÒÔÏàͬµÄËٶȿªÊ¼Ô˶¯Ê±Í¨¹ýµÄ¾àÀëΪ£¨n-1£©d£¬¶Ô¸ßËÙ¶¯³µ×éÔÚÁ¦F×÷ÓÃÏÂÆô¶¯Í¨¹ýÏàͬ¾àÀëµÄ¹ý³Ì£¬Óɶ¯Äܶ¨ÀíÓУº$F£¨n-1£©d=E_k^'-0$
½âµÃ$E_k^'=F£¨n-1£©d$£¬¹Ê$\frac{E_k^'}{E_k}=2$
´ð£º£¨1£©´«Í³ÁгµµÚ1½Ú³µÏáÓëµÚ2½Ú³µÏáÅöײºó˲¼ä£¬µÚ2½Ú³µÏáµÄËٶȴóСv2Ϊ$\sqrt{\frac{Fd}{2m}}$
£¨2£©´«Í³ÁгµËùÓгµÏᶼ¿ªÊ¼Ô˶¯Ê±µÄ×ܶ¯ÄÜEkΪ$\frac{£¨n-1£©}{2}Fd$
£¨3£©¸ßËÙ¶¯³µ×éÔÚÁ¦FµÄ×÷ÓÃÏÂÓɾ²Ö¹¿ªÊ¼Í¨¹ýÓ봫ͳÁгµÆô¶¯¹ý³Ì£¨´ÓÆô¶¯µ½ËùÓгµÏᶼ¿ªÊ¼Ô˶¯£©Ïàͬ¾àÀëʱµÄ¶¯ÄÜEk'ÒÔΪ£¨n-1£©Fd£¬$\frac{{{E_k}'}}{E_k}$Ϊ2

µãÆÀ £¨1£©±¾ÌâÖ÷Òª¿¼²éÁ˶¯Äܶ¨ÀíºÍ¶¯Á¿Êغ㶨ÂÉ
£¨2£©¹éÄɳöµÚn½Ú³µÏá±»´ø¶¯ºóµÄ˲ʱËÙ¶ÈÓëF¡¢d¡¢m¼°nµÄ¹ØϵÊǽâ¾öµÚ¶þÎʵĹؼü

Á·Ï°²áϵÁдð°¸
Ïà¹ØÏ°Ìâ

¿ÆÄ¿£º¸ßÖÐÎïÀí À´Ô´£º ÌâÐÍ£ºÑ¡ÔñÌâ

9£®Ò»ÖÊÁ¿Îª1kgµÄÖʵ㾲ֹÓڹ⻬ˮƽÃæÉÏ£¬´Ót=0ʱ¿Ì¿ªÊ¼£¬Êܵ½ÈçͼËùʾµÄˮƽÍâÁ¦×÷Óã¬ÏÂÁÐ˵·¨ÕýÈ·µÄÊÇ£¨¡¡¡¡£©
A£®µÚ1 sÄ©ÎïÌåµÄËÙ¶ÈΪ2m/s
B£®µÚ2sÄ©ÍâÁ¦×ö¹¦µÄ˲ʱ¹¦ÂÊ×î´ó
C£®µÚ1 sÄÚÓëµÚ2sÄÚÖʵ㶯Á¿Ôö¼ÓÁ¿Ö®±ÈΪ1£º2
D£®µÚ1 sÄÚÓëµÚ2sÄÚÖʵ㶯ÄÜÔö¼ÓÁ¿Ö®±ÈΪ4£º5

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖÐÎïÀí À´Ô´£º ÌâÐÍ£ºÊµÑéÌâ

16£®±¾×°ÖÃÖÐÒªÓõ½´òµã¼ÆʱÆ÷£¬ÆäÖÐÐèÒªÈçͼ1µçÔ´µÄ´òµã¼ÆʱÆ÷ÊÇͼ2ÖеÄÒÒ£®

ÔÚÀûÓôË×°Öá°Ì½¾¿¼ÓËÙ¶ÈaÓëÁ¦FºÍÖÊÁ¿mµÄ¹Øϵ¡±Ê±£¬ÊµÑéÖа´¹æ·¶²Ù×÷´ò³öµÄÒ»ÌõÖ½´øµÄÒ»²¿·ÖÈçͼ3£®ÒÑÖª´òµã¼ÆʱÆ÷½ÓÔÚƵÂÊΪ50HzµÄ½»Á÷µçÔ´ÉÏ£¬Aµã¶ÁÊýΪ18.40cm£¬´Ë´ÎʵÑéÖдòµã¼ÆʱÆ÷´òÏÂA µãʱС³µµÄ˲ʱËÙ¶ÈΪ0.63m/s£®£¨½á¹û±£Áô2λÓÐЧÊý×Ö£©

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖÐÎïÀí À´Ô´£º ÌâÐÍ£ºÑ¡ÔñÌâ

13£®¹ØÓÚµØÇòͬ²½ÎÀÐǵÄ˵·¨ÕýÈ·µÄÊÇ£¨¡¡¡¡£©
A£®ËùÓеØÇòͬ²½ÎÀÐÇÒ»¶¨ÔÚ³àµÀÉÏ¿Õ
B£®²»Í¬µÄµØÇòͬ²½ÎÀÐÇ£¬ÀëµØ¸ß¶È²»Í¬
C£®²»Í¬µÄµØÇòͬ²½ÎÀÐǵÄÏòÐļÓËٶȴóС²»ÏàµÈ
D£®ËùÓеØÇòͬ²½ÎÀÐÇÊܵ½µÄÏòÐÄÁ¦´óСһ¶¨ÏàµÈ

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖÐÎïÀí À´Ô´£º ÌâÐÍ£º¶àÑ¡Ìâ

20£®ÏÂÁÐ˵·¨ÕýÈ·µÄÊÇ£¨¡¡¡¡£©
A£®¹âÔÚͬÖÖ½éÖÊÖпÉÄÜÑØÇúÏß´«²¥
B£®²¨Óöµ½ÕÏ°­Îïʱ£¬Ò»¶¨»á·¢ÉúÑÜÉäÏÖÏó
C£®×öÊÜÆÈÕñ¶¯µÄÎïÌ壬Õñ¶¯ÆµÂÊÓë×ÔÉí¹ÌÓÐƵÂÊÓйØ
D£®±ä»¯µÄµç³¡¿ÉÄܲúÉú±ä»¯µÄ´Å³¡
E£®µç´Å²¨²»»á·¢ÉúÆ«ÕñÏÖÏó

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖÐÎïÀí À´Ô´£º ÌâÐÍ£ºÑ¡ÔñÌâ

10£®ÈçͼËùʾ£¬µ±Æû³µÊ»Ïòһ͹ÐÎÇÅʱ£¬ÎªÊ¹ÔÚͨ¹ýÇŶ¥Ê±£¬¼õСÆû³µ¶ÔÇŵÄѹÁ¦£¬Ë¾»úÓ¦£¨¡¡¡¡£©
A£®Ôö´óËٶȿìËÙͨ¹ýÇŶ¥B£®ÒÔÈκÎËÙ¶ÈÔÈËÙͨ¹ýÇŶ¥¶¼¿ÉÒÔ
C£®ÒÔ¾¡¿ÉÄÜСµÄËÙ¶Èͨ¹ýÇŶ¥D£®Ê¹Í¨¹ýÇŶ¥µÄÏòÐļÓËٶȾ¡¿ÉÄÜС

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖÐÎïÀí À´Ô´£º ÌâÐÍ£ºÑ¡ÔñÌâ

17£®Í¼¼×ΪһÁмòг²¨ÔÚt=0.10sʱ¿ÌµÄ²¨ÐÎͼ£¬PÊÇƽºâλÖÃΪx=1.0m´¦µÄÖʵ㣬QÊÇƽºâλÖÃΪx=4.0m´¦µÄÖʵ㣬ͼÒÒΪÖʵãQµÄÕñ¶¯Í¼Ïó£¬Ôò£¨¡¡¡¡£©
A£®ÔÚt=0.25sʱ£¬ÖʵãPµÄËٶȷ½ÏòΪyÖáÕý·½Ïò
B£®ÖʵãQ¼òгÔ˶¯µÄ±í´ïʽΪx=10sin$\frac{¦Ð}{2}$t£¨cm£©
C£®´Ót=0.10sµ½t=0.20s£¬¸Ã²¨ÑØxÖáÕý·½Ïò´«²¥ÁË4m
D£®´Ót=0.10sµ½t=0.25s£¬ÖʵãPͨ¹ýµÄ·³ÌΪ30cm

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖÐÎïÀí À´Ô´£º ÌâÐÍ£º½â´ðÌâ

14£®ÈçͼËùʾ£¬Á½ÌõÎÞÏÞ³¤Çҹ⻬µÄƽÐй̶¨½ðÊô¹ìµÀMN¡¢PQµÄµç×èΪÁ㣬Ïà¾àL=0.4m£¬Ë®Æ½·ÅÖÃÔÚ·½ÏòÊúÖ±ÏòÏ¡¢´Å¸ÐӦǿ¶ÈB=0.5TµÄÔÈÇ¿´Å³¡ÖУ¬ab£¬cdÁ½½ðÊô°ô´¹Ö±µØ¿ç·ÅÔÚµ¼¹ìÉÏ£¬µç×è¾ùΪR=0.5¦¸£¬abµÄÖÊ×îΪm1=0.4kg£¬cdµÄÖÊÁ¿Îªm2=0.1kg£¬¸øab°ôÒ»¸öÏòÓÒµÄ˲ʱ³åÁ¿£¬Ê¹Ö®ÒÔ³õËÙ¶Èv0=10m/s¿ªÊ¼»¬¶¯£¬µ±ab¡¢cdÁ½½ðÊô°ôËÙ¶ÈÏàµÈºó±£³ÖÔÈËÙÔ˶¯£¬Çó£º
£¨1£©ÔÚab°ô¸Õ¿ªÊ¼Ô˶¯Ê±£¬cd°ôµÄ¼ÓËٶȶà´ó£¿
£¨2£©´Óab°ô¸Õ¿ªÊ¼Ô˶¯µ½Á½½ðÊô°ôËÙ¶ÈÏàµÈÕâÒ»¹ý³Ì£¬µç·ÖÐÒ»¹²²úÉúÁ˶àÉÙ½¹¶úÈÈ£¿
£¨3£©´Óab°ô¸Õ¿ªÊ¼Ô˶¯µ½Á½½ðÊô°ôËÙ¶ÈÏàµÈÕâÒ»¹ý³Ì£¬Í¸¹ý»Ø·ÖеĵçÁ¿Îª¶àÉÙ£¿

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖÐÎïÀí À´Ô´£º ÌâÐÍ£ºÑ¡ÔñÌâ

15£®Á½¸öÁ¦F1¡¢F2µÄºÏÁ¦ÎªF£¬ÒÑÖªF1=20N£¬F=28N£¬ÄÇôF2µÄ´óС¿ÉÄÜÊÇ£¨¡¡¡¡£©
A£®4NB£®6NC£®18ND£®58N

²é¿´´ð°¸ºÍ½âÎö>>

ͬ²½Á·Ï°²á´ð°¸