9.肼是火箭发动机的一种燃料.反应时N2O4为氧化剂.生成N2和H2O(g).已知: N2,△H=+8.7kJ/mol, N2H4+2H2O(g),△H=-534.0kJ/mol, 下列表示肼跟N2O4反应的热化学反应方程式.正确的是 A.2N2H4 + 4H2O(g),△H=–542.7 kJ/mol B.2N2H4 + 4H2O(g),△H=–1059.3 kJ/mol C.N2H4(g) + N2O4(g)=N2,△H=–1076.7 kJ/mol D.2N2H4+ 4H2O(g),△H= –1076.7 kJ/mol 查看更多

 

题目列表(包括答案和解析)

肼(N2H4)是火箭发动机的一种燃料,反应时N2O4为氧化剂,生成N2和水蒸气。已知:

N2(g)+2O2(g)N2O4(g)  ΔH=+8.7 kJ·mol-1

N2H4(g)+O2(g) N2(g)+2H2O(g)  ΔH=-534.0 kJ·mol-1

下列表示肼跟N2O4反应的热化学方程式,正确的是 …(    )

A.2N2H4(g)+N2O4(g) 3N2(g)+4H2O(g)  ΔH=-542.7 kJ·mol-1

B.2N2H4(g)+N2O4(g) 3N2(g)+4H2O(g)  ΔH=-1 059.3 kJ·mol-1

C.N2H4(g)+N2O4(g) N2(g)+2H2O(g)  ΔH=-1 076.7 kJ·mol-1

D.2N2H4(g)+N2O4(g) 3N2(g)+4H2O(g)  ΔH=-1 076.7 kJ·mol-1

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肼(N2H4)是火箭发动机的一种燃料,反应时N2O4为氧化剂,生成N2和水蒸气。已知:?

N2(g)+2O2(g) ══N2O4(g);ΔH=+8.7 kJ·mol -1

N2H4(g)+O2(g) ══N2(g)+2H2O(g);ΔH=-534.0 kJ·mol -1???

下列表示肼跟N2O4反应的热化学方程式,正确的是

A.2N2H4(g)+N2O4(g) ══3N2(g)+4H2O(g);ΔH=-542.7 kJ·mol -1??

B.2N2H4(g)+N2O4(g) ══3N2(g)+4H2O(g);ΔH=-1059.3 kJ·mol -1??

C.N2H4(g)+ N2O4(g) ══N2(g)+2H2O(g);ΔH=-1076.7 kJ·mol -1??

D.2N2H4(g)+N2O4(g) ══3N2(g)+4H2O(g);ΔH=-1076.7 kJ·mol -1?

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肼(N2H4)是火箭发动机的一种燃料,反应时N2O4为氧化剂,生成N2和水蒸气。已知:

N2(g)+2O2(g)====N2O4(g);ΔH=+8.7 kJ·mol-1

N2H4(g)+O2(g)====N2(g)+2H2O(g);ΔH=-534.0 kJ·mol-1

下列表示肼跟N2O4反应的热化学方程式,正确的是(    )

A.2N2H4(g)+N2O4(g)====3N2(g)+4H2O(g);ΔH=-542.7 kJ·mol-1

B.2N2H4(g)+N2O4(g)====3N2(g)+4H2O(g);ΔH=-1 059.3 kJ·mol-1

C.N2H4(g)+N2O4(g)====N2(g)+2H2O(g);ΔH=-1 076.7 kJ·mol-1

D.2N2H4(g)+N2O4(g)====3N2(g)+4H2O(g);ΔH=-1 076.7 kJ·mol-1

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肼(N2H4)是火箭发动机的一种燃料,反应时N2O4为氧化剂,生成N2和水蒸气。已知:N2(g)+2O2(g)=N2O4(g) ΔH="+8.7" kJ·mol-1
N2H4(g)+O2(g)=N2(g)+2H2O(g) ΔH="-534.0" kJ·mol-1
下列表示肼跟N2O4反应的热化学方程式,正确的是  (     )

A.2N2H4(g)+N2O4(g)=3N2(g)+4H2O(g)ΔH="-542.7" kJ·mol-1
B.2N2H4(g)+N2O4(g)=3N2(g)+4H2O(g)ΔH="-1059.3" kJ·mol-1
C.N2H4(g)+N2O4(g)=N2(g)+2H2O(g)ΔH="-1076.7" kJ·mol-1
D.2N2H4(g)+N2O4(g)=3N2(g)+4H2O(g)ΔH="-1076.7" kJ·mol-1

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肼(N2H4)是火箭发动机的一种燃料,反应时N2O4为氧化剂,生成N2和水蒸气。已知:
N2(g)+2O2(g)====N2O4(g)   ΔH="+8.7" kJ·mol-1
N2H4(g)+O2(g) ====N2(g)+2H2O(g)  ΔH="-534.0" kJ·mol-1
下列表示肼跟N2O4反应的热化学方程式,正确的是

A.2N2H4(g)+N2O4(g) ====3N2(g)+4H2O(g) ΔH="-542.7" kJ·mol-1
B.2N2H4(g)+N2O4(g) ====3N2(g)+4H2O(g)ΔH="-1059.3" kJ·mol-1
C.N2H4(g)+N2O4(g) ====N2(g)+2H2O(g)ΔH="-1076.7" kJ·mol-1
D.2N2H4(g)+N2O4(g) ====3N2(g)+4H2O(g)ΔH="-1076.7" kJ·mol-1

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