题目列表(包括答案和解析)
已知:O2(g)= O2+(g)+e- H1= +1175.7 kJ·mol-1
PtF6-(g)=PtF6(g)+e- H2= +771.1 kJ·mol-1
O2+(g)+PtF6-(g)=O2PtF6(S) H3= -482.2 kJ·mol-1
则反应O2(g)+PtF6(g)= O2PtF6 (s)的H是( )
A.77.6 kJ B.-77.6 kJ·mol-1 C.+77.6kJ·mol-1 D.-886.8kJ·mol-1
已知:O2(g) = O2+(g)+e- H1=" +1175.7" kJ·mol-1
PtF6-(g) =PtF6(g)+e- H2=" +771.1" kJ·mol-1
O2+(g)+PtF6-(g) =O2PtF6(S) H3=" -482.2" kJ·mol-1
则反应O2(g)+PtF6(g) = O2PtF6 (s)的H是
A.77.6 kJ | B.-77.6 kJ·mol-1 | C.+77.6kJ·mol-1 | D.-886.8kJ·mol-1 |
已知:O2(g) = O2+(g)+e- H1=" +1175.7" kJ·mol-1
PtF6-(g) =PtF6(g)+e- H2=" +771.1" kJ·mol-1
O2+(g)+PtF6-(g) =O2PtF6(S) H3=" -482.2" kJ·mol-1
则反应O2(g)+PtF6(g) = O2PtF6 (s)的H是( )
A.77.6 kJ | B.-77.6 kJ·mol-1 | C.+77.6kJ·mol-1 | D.-886.8kJ·mol-1 |
湖北省互联网违法和不良信息举报平台 | 网上有害信息举报专区 | 电信诈骗举报专区 | 涉历史虚无主义有害信息举报专区 | 涉企侵权举报专区
违法和不良信息举报电话:027-86699610 举报邮箱:58377363@163.com