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    解:(1)如图4.连结 ······································································ 1分 .······································· 2分 是的直径(也可用勾股定理求得下面的结论) . ················································· 3分 ..········································ 4分 (2)过点 ·········································· 5分 当时. ··········································· 6分 . (也可用勾股定理逆定理证明)······························· 7分 是的切线······················································································· 8分 (3)过点 ···························································· 9分 ························································································· 10分 【查看更多】

     

    题目列表(包括答案和解析)

    在如图所示的平面直角坐标系中，点C在y轴的正半轴上，四边形OABC为平行四边形，OA=2，∠AOC=60°，以OA为直径的⊙P经过点C，交BC于点D，DE⊥AB，交AB于E．
    （1）求点A和B的坐标；
    （2）求证：DE是⊙P的切线；
    （3）小明在解答本题时，发现连结DA并延长，交x轴于点N，则△AON是等腰三角形．由此，他断定：“x轴上一定存在除点N以外的点Q，使△AOQ也是等腰三角形，且点Q一定在⊙P外”．你同意他的看法吗？请充分说明理由．

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    在如图所示的平面直角坐标系中，点C在y轴的正半轴上，四边形OABC为平行四边形，OA=2，∠AOC=60°，以OA为直径的⊙P经过点C，交BC于点D，DE⊥AB，交AB于E．
    （1）求点A和B的坐标；
    （2）求证：DE是⊙P的切线；
    （3）小明在解答本题时，发现连结DA并延长，交x轴于点N，则△AON是等腰三角形．由此，他断定：“x轴上一定存在除点N以外的点Q，使△AOQ也是等腰三角形，且点Q一定在⊙P外”．你同意他的看法吗？请充分说明理由．

    查看答案和解析>>


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