26.如图所示.在平面直角坐标系中.抛物线()经过..三点.其顶点为.连接.点是线段上一个动点(不与重合).过点作轴的垂线.垂足为.连接. (1)求抛物线的解析式.并写出顶点的坐标, (2)如果点的坐标为.的面积为.求与的函数关系式.写出自变量的取值范围.并求出的最大值, 的条件下.当取得最大值时.过点作的垂线.垂足为.连接.把沿直线折叠.点的对应点为.请直接写出点坐标.并判断点是否在该抛物线上. (2009年辽宁本溪26题解析)26.解:(1)设.·························· 1分 把代入.得.························································································· 2分 ∴抛物线的解析式为:.···································································· 4分 顶点的坐标为.································································································ 5分 (2)设直线解析式为:().把两点坐标代入. 得·············································································································· 6分 解得. ∴直线解析式为.··············································································· 7分 .······················································· 8分 ∴····························································································· 9分 .···························································· 10分 ∴当时.取得最大值.最大值为.······························································ 11分 (3)当取得最大值...∴.·················································· 5分 ∴四边形是矩形. 作点关于直线的对称点.连接. 法一:过作轴于.交轴于点. 设.则. 在中.由勾股定理. . 解得. ∵. ∴. 由.可得.. ∴. ∴坐标.································································································ 13分 法二:连接.交于点.分别过点作的垂线.垂足为. 易证. ∴. 设.则. ∴.. 由三角形中位线定理. . ∴.即. ∴坐标.································································································ 13分 把坐标代入抛物线解析式.不成立.所以不在抛物线上.·················· 14分 查看更多

 

题目列表(包括答案和解析)

(2009年本溪)
“五·一”期间,九年一班同学从学校出发,去距学校6千米的本溪水洞游玩,同学们分为步行和骑自行车两组,在去水洞的全过程中,骑自行车的同学比步行的同学少用40分钟,已知骑自行车的速度是步行速度的3倍.

(1)求步行同学每分钟走多少千米?
(2)上图是两组同学前往水洞时的路程(千米)
与时间(分钟)的函数图象.
完成下列填空:
①表示骑车同学的函数图象是线段         ;
②已知点坐标,则点的坐标为(     ).

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(2009年本溪)
“五·一”期间,九年一班同学从学校出发,去距学校6千米的本溪水洞游玩,同学们分为步行和骑自行车两组,在去水洞的全过程中,骑自行车的同学比步行的同学少用40分钟,已知骑自行车的速度是步行速度的3倍.

(1)求步行同学每分钟走多少千米?
(2)上图是两组同学前往水洞时的路程(千米)
与时间(分钟)的函数图象.
完成下列填空:
①表示骑车同学的函数图象是线段         ;
②已知点坐标,则点的坐标为(     ).

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(2009•本溪)2009年6月,全国参加高等院校统一招生考试的学生约10 200 000人,其中10 200 000用科学记数法表示应为( )
A.10.2×106
B.1.02×108
C.0.102×108
D.1.02×107

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(2010•本溪)为执行“两免一补”政策,丹东地区2007年投入教育经费2 500万元,预计2009年投入3 600万元,则这两年投入教育经费的平均增长率为( )
A.10%
B.20%
C.30%
D.15%

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(2010•本溪)为执行“两免一补”政策,丹东地区2007年投入教育经费2 500万元,预计2009年投入3 600万元,则这两年投入教育经费的平均增长率为( )
A.10%
B.20%
C.30%
D.15%

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