练习册

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    解:(1)P6．··················································································· 2分 (2)······································································ 4分 (3)由题意知.旋转次之后回到轴正半轴.在这次中.点分别落在坐标象限的平分线上或轴或轴上.但各点绝对坐标的横.纵坐标均为非负数.因此.点的坐标可分三类情况: 令旋转次数为 ①当或时(其中为自然数).或当点落在轴上. 此时.点的绝对坐标为,········································································· 6分 ②当或或或时(其中为自然数).或当点落在各象限的平分线上. 此时.点的绝对坐标为···························································· 8分 ③当或时(其中为自然数).或当点落在轴上. 此时.点的绝对坐标为．······································································· 10分 【查看更多】

     

    题目列表(包括答案和解析)

    11、写出一个既能用直接用开平方法解，又能用因式分解法解的一元二次方程是
    x2-64=0
    ．

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    解方程组
    x+y
    2
    +
    x-y
    3
    =6
    4(x+y)-5(x-y)=2
    ．

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    解方程组
    x+y
    2
    +
    x-y
    3
    =6
    4(x+y)-5(x-y)=2
    ．

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    解下列关于方程的问题
    （1）解方程：16（x-2）2=64；
    （2）解方程：2x2+x-1=0；
    （3）已知关于x的方程x2+px-q=0的两个根是0和-3，求p、q的值．

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    解方程：
    ①5x-2=8
    ②
    x-6
    4
    -x=
    x+5
    2
    ．

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