设函数f(x)满足f(n+1)=(n∈N),且f(1)=2,则f(20)等于(    )

A.95                                   B.97                             C.105                           D.192

设函数f(x)满足f(n+1)=(n∈N^*),且f(1)=2,则f(20)等于(    )

A.95              B.97             C.105                 D.192

若函数f(x)满足f(x+3)+f(x-3)=2x²-8x+8,f(x+3)-f(x-3)=4(x-2),且f(a-1),1,f(a+1)是一个递增的等差数列{a_n}的前三项.

(1)求数列{a_n}的通项公式;

(2)记T_n=(n＞1,n∈N^*),设g(n)=T_2n+1-T_n+1,试确定实数m的取值范围,使得对于一切大于1的自然数n,不等式g(n)＞［log_m(m-1)］²-恒成立.