+1/2O2,ΔH=-348.3kJ/mol +1/2 O2(g)== Ag2O(s),ΔH=-31.0kJ/mol 则Zn(s)+ Ag2O的ΔH等于( ) A.-317.3kJ/mol B.-379.3kJ/mol C.-332.8 kJ/mol D.+317.3 kJ/mol [答案]A [解析]由已知⑴. ⑵热化学方程式可知:⑴-⑵ 即可得出答案. [考点分析]本题考查了热化学方程式书写规律. 查看更多

 

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已知: (1)Zn(s)+1/2O2(g)==ZnO(s);ΔH=-348.3kJ/mol

(2)2Ag(s)+1/2 O2(g)== Ag2O(s);ΔH=-31.0kJ/mol

则Zn(s)+ Ag2O(s)== ZnO(s)+ 2Ag(s)的ΔH等于(   )

A.-317.3kJ/mol B.-379.3kJ/mol C.-332.8 kJ/mol       D.+317.3 kJ/mol

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已知:

(1)Zn(s)+1/2O2(g)==ZnO(s);ΔH=-348.3kJ/mol

(2)2Ag(s)+1/2 O2(g)== Ag2O(s);ΔH=-31.0kJ/mol

则Zn(s)+ Ag2O(s)== ZnO(s)+ 2Ag(s)的ΔH等于(   )

A.-317.3kJ/mol          B.-379.3kJ/mol     C.-332.8 kJ/mol    D.+317.3 kJ/mol

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已知:

(1)Zn(s)+1/2O2(g)=ZnO(s);ΔH=-348.3kJ/mol

(2)2Ag(s)+1/2 O2(g)= Ag2O(s);ΔH= -31.0kJ/mol

则Zn(s)+ Ag2O(s)= ZnO(s)+ 2Ag(s)的ΔH等于(      )

A.-317.3kJ/mol B.-379.3kJ/mol C.-332.8 kJ/mol       D.+317.3 kJ/mol

 

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已知:
(1)Zn(s)+1/2O2(g)=ZnO(s);ΔH=-348.3kJ/mol
(2)2Ag(s)+1/2 O2(g)= Ag2O(s);ΔH= -31.0kJ/mol
则Zn(s)+ Ag2O(s)= ZnO(s)+ 2Ag(s)的ΔH等于(     )

A.-317.3kJ/molB.-379.3kJ/molC.-332.8 kJ/molD.+317.3 kJ/mol

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