练习册

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    已知函数.若x=0.函数f(x)取得极值 (Ⅰ)求函数f(x)的最小值, (Ⅱ)已知证明:. 解:(Ⅰ) 由 x=0是极值点.故,得 故 m=1. 故 当 -1＜x＜0时.函数在内是减函数, 当 x＞0时.函数f(x)在内是增函数. 所以x=0时.f(0)=0.则函数f(x)取得最小值为0.·························6分 知:f(x)≥0.故ex-1≥ln(x+1). ∵①··············8分 又 = 故 ················································10分 故 ② 由①②得 ···········································12分 【查看更多】

     

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