五.综合题 查看更多

 

题目列表(包括答案和解析)

现准备用“伏安法”测量额定电压为2.5V的小灯泡的电阻,实验室能提供的实验器材有:

A.待测小灯光L(其正常工作时的电阻值约为10Ω);

B.二节新的干电池串联(每节干电池的电压为1.5V);

C.电压表一个(量程为0~3V,0~15V,电阻为5KΩ);

D.电流表一个(量程为0~0.6A,0~3A,电阻为5Ω);

E.滑动变阻器R0(阻值为0~50Ω,额定电流为1A);

F.开关S一个,导线若干.则:

(1)如果使用上述器材来测量小灯泡的电阻,那么,当小灯泡正常工作时,该电路中的电流约为   A,因此,电流表的量程应选0~   A。

(2)由于电流表和电压表都有一定的电阻,严格来说将它们接入电路后,对电路都要产生一定的影响。那么,为了减少误差,在甲、乙所示的电路图(未画完)中,最好选 

(选填“甲”或“乙”)。 新 课 标 第 一网

(3)根据以上选择的电路图,在丙图中用铅笔画线代替导线进行连线,使之成为能比较精确地测量出小灯泡电阻的电路(其中,部分导线已连接)。

(4)在实验中,某同学设计的实验报告及实验记录数据如下表所示。

实验名称

用“伏安法”测量小灯泡的电阻

实验目的

练习使用电流表和电压表测量小灯泡的电阻

实验步骤

a、按照电路图连接电路,调节滑动变阻器的滑片P,使电路中的  最小。

b、闭合开关,调节滑片P,使小灯泡两端的电压达到   V,然后,测量从额定电压开始逐次     (选填“降低”或“升高”),获得几组数据。

c、根据测出的电压值和电流值,求出小灯泡的电阻。

实验记录

电压U/V

电流I/A

电阻R/Ω

2.5

0.26

9.6

2.0

0.24

8.3

1.5

0.2

7.5

1.0

0.15

6.7

①将实验步骤中的空格填写完整。

②从实验记录中可以看出,存在明显错误的记录数字是    

③根据实验记录数据,采用“描点法”在如图所示的坐标系中,作出小灯泡的U—I图像。

四、计算题(本题共2小题,共12分。解答时应写出必要的文字说明、公式和重要的演算步骤。只写出最后结果的不能得分。有数值运算的题,答案中必须写出数值和单位。)

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    (说明:若你认为“方案”可行,则选A解答,若你认为“方案”不可行,则选B解答)

一、不定项选择题(本题共6小题,每小题2分,共12分。在每小题给出的四个选项中,至少有一个选项是符合题目要求的,全部选对的得2分,只有一个正确答案的得1分,有选错或不答的得0分。)[来源:全品高考网 GK.CANPOINT.CN]

【题文】下列关于电磁现象的说法中,正确的是

A.导线周围始终存在磁场

B.发电机是根据电磁感应现象制成的

C.电磁铁磁性的强弱与电磁铁线圈的匝数有关

D.只要导体在磁场中运动,就会产生感应电流

 

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第二节 (共5小题;每小题2分,满分10分)
根据短文内容,从短文后的选项中选出能填入空白处的最佳选项。选项中有两项为多余选项。
Why do some people have many friends while others do not? ___71___ However, it is not so. Let’s look at two psychological experiments which will give you the key to happy interpersonal relations.
The first experiment is called the “Hawthorne effect” after Hawthorne, Illinois(伊利诺斯[美国州名]), where the experiment took place. A group of psychologists examined the work patterns of two groups of workers in the Western Electric Company. ____72_____. The psychologists changed the working conditions for one group twice but left the other group alone. They were surprised to find that productivity increased on both occasions and in both groups. They concluded that the increase in productivity came from the attention given to the workers by the management. It had increased their motivation and so they had worked harder. In other words, if you take an interest in others, they will want to please you and you will have good relations with them.
___73___. After Martin Luther King, Jr was killed in 1960s, a teacher, Jane Elliott, living in an all- white town decided to help her class of young children understand why the Civil Rights Movement had been necessary in America.
She divided the class into two groups: one with blue eyes and other with brown eyes. Other eye colors such as hazel or green were excluded from his exercise. Then she told the class that brown-eyed people were cleverer than blue-eyed ones because of an agent(化学作用) for brown color found in their blood. Blue-eyed people were stupid, lazy and not to be trusted. Jane Elliott did not need to say any more. The brown-eyed students quickly got used to their new role as the leaders of the class. The blue-eyed students became quiet and withdrawn. Then she discovered something very interesting. Four poor brown-eyed readers began to read fluently in a way they had never done before. ___74___. So if you want to be successful and happy, take an interest in others whether they are your classmates or workmates. Congratulate them on their success and sympathize with them in their troubles. ___75___.
A.Before the experiment the management talked to both groups of workers and explained that they wanted to find the best working environment for them.
B.Remember that the way you treat others will decide their attitude and behavior to you.
C.The second experiment shows what happens to personal relations if you are rude to or ignore others.
D.The ones who have more friends usually are those who care about others.
E. Jane Elliott had shown that the way people are treated affects not only their behavior but also their confidence and their performance.
F. You may even imagine that this ability was something they were born with because it seems so effortless to them.
G. The second experiment tells us what teachers said had a great effect on the students.

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计算题(本题共3小题,共20分)

(6分)某电热水器,额定功率为2000W。当热水器正常工作70min时,可将50kg的水从

  20℃加热到58~C。水的比热容为4.2×103 J/(kg·℃)。试求:

  (1)这50kg水吸收的热量是多少?

  (2)热水器消耗的电能是多少?

  (3)热水器的效率是多少?

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    (说明:若你认为“方案”可行,则选A解答,若你认为“方案”不可行,则选B解答)

一、不定项选择题(本题共6小题,每小题2分,共12分。在每小题给出的四个选项中,至少有一个选项是符合题目要求的,全部选对的得2分,只有一个正确答案的得1分,有选错或不答的得0分。)

【题文】下列关于电磁现象的说法中,正确的是

A.导线周围始终存在磁场

B.发电机是根据电磁感应现象制成的

C.电磁铁磁性的强弱与电磁铁线圈的匝数有关

D.只要导体在磁场中运动,就会产生感应电流

 

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