25.As he has ______ good knowledge of ______ French language, he will be sent to work in France.
A. /; / B. a; the C. a; / D. / ; the
24. My grandma still treats me like a child. She can’t imagine __________ grown up.
A. my B. mine C. myself D. me
23. E-mail, as well as telephones, ___________ an important part in daily communication.
A. is playing B. have played C. are playing D. play
22. __________ snacks and drinks, but they also brought cards for entertainment when they had a picnic in the forest.
A. Not only they bought B. Not only did they bring
C. Not only brought they D. Not only they did bring
第一节:单项填空(共15小题;每小题1分,满分15分)
从A、B、C、D四个选项中,选出可以填入空白下的最佳选项,并在答题卡上将该项涂黑。
21. He accidently _________ that he had quarreled with his wife and that he hadn’t been home for a couple of weeks.
A. let out B. took care C. made sure D. made out
12.(18分)如图所示,竖直平面上有相互垂直的匀强电场和匀强磁场,电场强度
E1=2500N/C,方向竖直向上;磁感应强度B=103T,方向垂直纸面向外;有一质量m=1×10-2kg、电荷量q=4×10-5C的带正电小球自O点沿与水平线成45°以v0=4m/s的速度射入复合场中,之后小球恰好从P点进入电场强度E2=2500N/C,方向水平向左的第二个匀强电场中.不计空气阻力,g取10m/s2.求:
⑴O点到P点的距离s1;
⑵小球经过P点的正下方Q点时与P点的距离s2.
11.(18分)如图所示,水平面分为两个区,P线左侧为粗糙区,右侧为光滑区.紧靠P线在左侧上放一长L1=1m、质量M1=3kg的长木板B,在右侧上放一质量M2=3kg的长木板C.B、C不粘连.在长木板B的左端放一可看作质点的质量m=2kg的小木块A.已知B与A、B与水平面、C与A之间的滑动摩擦因数均为μ=0.2.现给A施加一个F=8N的水平恒力,经1s后就撤去该恒力.
⑴.求1s末A获得的速度v1;
⑵.为了保证A不会从C上掉下,长木板C的最小长度L2为多少?
解:
(非选择题部分3小题,共54分。按题目要求作答,计算题应写出必要的文字说明、方程式和重要步骤,只写出最后答案的不能得分。有数值计算的题,答案中必须明确写出数值和单位。)
10.(18 分)(1)(6分)在利用重物自由下落“验证机械能守恒定律”的实验中,打点计时器所用电源频率为50Hz,实验要求打点计时器在打第一个点时释放纸带.甲、乙、丙三个学生分别用同一装置各打出一条纸带,量出各纸带上第1、2两点间的距离分别为0.48cm,0.19cm和0.18cm,肯定其中一个学生在操作上有错误,该同学是_____.其错误的操作是________________________________________________.
(2)(12分)要测定某电源的电动势和内电阻,以下提供的器材有:
A.待测电源E(E约为2V,r约为1Ω)
B.电流表A1(量程为0.6A,RA1=3Ω)
C.电流表A2(量程为0.3A,RA2约为5Ω)
D.电阻箱R(0~99Ω)
E.开关S1、S2 F.导线若干
(I)(6分)有一组同学按如右电路图进行如下实验:
①闭合开关S1,多次调节电阻箱的阻值,并记录下每次的电阻值R及对应的电流表A1的示数I;
②把电流换算成倒数,和电阻箱阻值R一起填入如下的表格中.
R/Ω |
1 |
2 |
3 |
4 |
5 |
6 |
/ A-1 |
2.5 |
3.0 |
3.6 |
4.0 |
4.5 |
5.0 |
③请把表格的数据在方格纸中作出-R图象;
④由-R图象求出:电源的电动势
E= V,内电阻r= Ω.
(Ⅱ)(6分)有另一组同学采用两个电流表和两个开关测定本电源的电动势和内电阻.
①请从提供的实验器材中选择合适的两个电流表分别填入右边实验电路图的圆框中.
②闭合开关S1,断开S2,读出电流表 的示数为I1;
③再闭合开关S2,读出该支路电流表的示数为I2及原先支路电流表的示数为I1′;
④由此可得到电源电动势的表达式E= .
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