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69. The Queen presented the prizes     (亲自). 

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68. My     (指示) are that I am not to let anyone in. 

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67. Success is     (取决于) on how hard you work.  

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66. Each ticket     (许可) two people to the party. 

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5. conclusion  A. lose  B. student  C. suggestion  D. pleasure

第二节 补全对话 (共5小题;每小题1分,满分5分)

根据对话内容,从对话后的选项中选出能填入空白处的最佳选项,并在答题卡上将该项涂黑。选项中有两项为多余选项。

-- Professor Smith, I have a record of my studies for last year?

-- Would you like to see it?

-- Yes, sir.

-- John,  61   

-- Yes, sir. But I’d like to apply to admission to Cambridge University.

-- I see.  62 

-- Yes, Mr. Smith. They think it’s a very good idea.

-- Well, your record here has been very good.  63   

--  64   Anyway, I’m going to apply. And I’d like to ask you to write a recommendation(推荐信) for me if it is not too much trouble.

--  65   

-- Thank you very much, Professor.

-- All right. Good luck to you.

A. I don’t think you’ll have much trouble.

B. Are you getting on well with your studies?

C. I hope not.

D. You are studying mathematics, aren’t you?

E. I’d like to talk with you about my studies for a minute, if I may.

F. Have you asked your parents for their advice?

G. Not at all. I’d be glad to.

第三节  单词拼写(10小题,每小题1分;满分10分)

   根据下列句子及所给汉语注释,在答题卡上相应题号的横线上写出空缺处各单词的正确形式。(每空只写一词)

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4. ocean  A. other  B. often  C. only  D. occur

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3. breathe  A. wealth  B. although  C. thin  D. mathematics

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2. treat  A. season  B. ahead  C. ear  D. break

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1. fat  A. nation  B. natural  C. hate  D. ashamed

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2.(1)近期媒体报道,叛逃到英国的俄罗斯前特工利特维年科在伦敦离奇身亡.英国警方调查认为,毒杀利特维年科的是超级毒药--放射性元素钋(Po).Po的半衰期为138 d,经衰变生成稳定的铅(Pb),那么经过276 d,100 g Po已衰变的质量为________g.

(2)一个氘核(H)和一个氚核(H)结合成一个氦核并放出一个中子时,质量亏损为Δm,已知阿伏加德罗常数为NA,真空中的光速为c,若1 mol氘和1 mol氚完全发生上述核反应,则在核反应中释放的能量为________.

A.NAΔmc2    B.2NAΔmc2   C.NAΔmc2    D.5NAΔmc2

(3)用速度为v0、质量为m1的He核轰击质量为m2的静止的7N核,发生核反应,最终产生两种新粒子A和B.其中A为8O核,质量为m3,速度为v3;B的质量为m4.

①计算粒子B的速度vB.

②粒子A的速度符合什么条件时,粒子B的速度方向与He核的运动方向相反.

解析:(1)根据半衰期的定义,经过276 d(两个半衰期),100 g Po已衰变的质量为+=75 g.

(2)根据爱因斯坦的质能方程,一个氘核(H)和一个氚核(H)结合成一个氦核并放出一个中子释放的能量为Δmc2,1 mol氘和1 mol氚完全发生上述核反应,释放的能量为上述反应的NA倍,即NAΔmc2.

(3)①由动量守恒定律有:m1v0m3v3+m4vB,解得:vB=.

②B的速度与He核的速度方向相反,即:m1v0m3v3<0,解得:v3>.

答案:(1)75 (2)A (3)① ②v3>

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