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15. ---I am really proud of our country!

---I feel the same way. That was the first time that the Chinese people ________ in space.

A. walk
B. walked
C. had walked
D. have walked

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14. Tom was not present ___ school ____ his injured leg.

A. at, because
B. at, because of
C. from, because
D. from, because of

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13. It was so nice to hear from her. ______, we last met more than 30 years ago.

A. What’s more
B. That is to say
C. In other words
D. Believe it or not

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12. ---Excuse me, what did the teacher ask Tom after class?    ---She asked him_________.

A. if had he finished his homework
B. whether he had finished his homework
C. that he finished his homework
D. if you have finished your homework

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第一节:单项选择(共14小题;每小题1分,满分14分)

11. --- I am afraid I can’t finish the book within this week.      ---_______.

A. Please go ahead
B. That’s all right
C. Not at all
D. Take your time.

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第一节(共5小题,每小题1分,满分5分)

请听下面5段对话,选出最佳选项。

1. Where does this conversation take place?

  A. At a hospital.      B. At a department store.     C. At a restaurant.

2. How much is the food and drink?

  A..$2.65.            B. $2.75.           C. $2.95.

3. What's the man doing?

  A. Watching TV.      B. Turning down the TV.     C. Answering the phone.

4. According to the man, what does he like to do if possible?

  A. To visit museums.      B. To make a good plan.

  C. To visit the Modern Museum.

5. What news did the woman get from the man?

  A. Sam will leave New York very soon.

  B. Sam's sister will leave for Los Angeles very soon.

  C. Sam' s sister will leave for New York very soon.

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23.(10分)正以v=30m/s的速度运行中的列车,接到前方小站的请求:在该站停靠1分钟接一位危重病人上车,司机决定以加速度a1= 0.6m/s2匀减速运动到小站,停车1分钟后以a2 = 1.0m/s2匀加速起动,恢复到原来的速度行驶,试问由于临时停车共耽误了多少时间?

蓬街私立中学2009学年第一学期第一次月半考

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22.(10分)汽车刹车后,停止转动的轮胎在地面上发生滑动,可以明显的看出滑动的痕迹,即常说的刹车线,由刹车线长短可以得知汽车刹车前的速度大小,因此刹车线的长度是分析交通事故的一个重要依据。某一特殊路段的最高限制速度为40km/h,有一辆汽车遇紧急情况刹车,若汽车刹车后以7 m/s2的加速度运动,刹车线长14m,假如你是一位交警,请你通过计算求出汽车刹车前的速度v0  ,来判断卡车是否超速违章行驶?

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21.(9分)为了测量一高楼的高度,有人设计了如下实验:在一根长为l的绳两端各拴一重球,一人站在楼顶上,手执绳的上端使小球与楼顶平齐并无初速释放,使其自由下落,另一个人在楼下测量两球落地的时间差△t,即可根据l、△tg得出楼的高度(不计空气阻力).从原理上讲,这个方案是否正确?若测得l=10m,△t=0.4s,g=10m/s2,试估算楼的高度.

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