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第二节  听取信息(共5小题;每小题1分,满分5分)

听下面一段独白,请根据题目要求,从所听到的内容中获取必要的信息,填入答题卡标号为16-20的空格中。听录音前,你将有10秒钟的阅题时间,录音读两遍。你将有60秒钟的作答时间。

Items
Answers
The main reason for having the fair
16. To_______________________
When to have the fair
17. _________________________
Where to have the fair
18. The university __________________
What to donate at the auction(拍卖会)
19. __________________________
Activities for children
20. __________________________

试题详情

第一节  听力理解(5段共15小题;每小题2分,满分30分)

每段播放两遍。各段后有几个小题,各段播放前每小题有5秒钟的阅题时间。请根据各段播放内容及其相关小题,在5秒钟内从题中所给的A、B、C项中,选出最佳选项,并在答题卡上将该项涂黑。

听第一段对话,回答第1至3题。

1.What is main topic of the dialogue?

  A. Anxiety    B. Sympathy   C. Examination

2. Why does Jack turn to Grace for help?

  A. She is older than he is.

  B. She has had a similar experience.

  C. She is a medical student

3. What does the school offer to students in Jack’s condition?

  A. A course about how to handle stress.

  B. A book on how to deal with anxiety.

  C. A lecture on how to cope with stress. 

听第二段对话,回答第4至6题。

4.What did the man do after he read the newspapers that morning?

  A. Went to his office.   B. Turned on the computer.   C. Checked his e-mail.

5. How did the man know there was a big fire in Hong Kong yesterday?

A. His father sent him the message.

B. He got the news from his brother.

  C. He read it from the newspaper.

6.Where does the conversation take place?

A. At the man’s home. 

B. At the airline reservation agency.

C. At the man’s office.

听第三段独白,回答第7至9题。

7. What does the speaker mainly focus on?

A. Haka, an ancient Maori dance.

B. Maori people, native New Zealanders.

C. A match between Italy and New Zealand.

8. Why do the All Blacks players perform before a rugby match really starts?

A. They want to get their fans excited.

B. They want to tell the enemy they are violent.

C. They want to make the enemy frightened.

9. What can you conclude from the speaker?

A. In order to be successful, now all opponents look down upon the war dance.

B. Italians didn’t think much of the war dance, so the Italians won the match.

C. The war dance still played a role in the match between Italy and New Zealand.

听第四段对话,回答第10至12题。

10. What does the man want to do?

A. Play basketball with friends from work.

B. Try out for the company basketball team.

C. Get in shape and compete in a cycling race.

11. What’s the woman’s main concern?

A. She is worried her husband will spend too much time away from home.

B. She is afraid her husband will become a fitness fan.

C. She is concerned about her husband’s health.

12. What does the woman advise about the man’s diet?

A. He should eat less salt.

B. He should eat less fatty foods.

C. He should add more protein products to his diet.

听第五段独白,回答第13至15题。

13. How is the melting of Arctic sea ice going on?

A. It’s slowing down.   B. It has stopped.   C. It’s accelerating.

14. What can we learn from the speaker?

A. The colder weather in the northern hemisphere has caused less melting of Arctic sea ice.

B. The latest data shows that Arctic sea ice is not melting as fast as before.

C. In the past few months the Arctic sea ice has been melting faster than last summer.

15. What disaster has the melting of Arctic sea ice caused?

  A. Drought in some areas.   B. Flood in some areas.   C. Colder weather. 

试题详情

36.(1)带电小球在正交的匀强电场和匀强磁场中因受到的重力Gmg=0.1N (1分)

电场力F1qE1=0.1N     (1分)

GF1,故小球在正交的电磁场中由AC做匀速圆周运动.(2分)

根据牛顿第二定律得:    (2分)

解得:  R (1分)

由几何关系得:(2分)

(2)带电小球在C点的速度大小仍为v0=4m/s,方向与水平方向成45°.由于电场力F2qE2=0.1N,与重力大小相等,方向相互垂直,则合力的大小为F,方向与初速度垂直,故小球在第二个电场中作平抛运动.(2分)

建立如图所示的x、y坐标系.

沿y方向上,

小球的加速度a=F/m=(1分),

位移y=(1分)

沿x方向上,小球的位移x=v0t(1分)

由几何关系有:(1分)

即:v0t,解得:t=0.4s(1分)

Q点到P点的距离s2.(2分)

试题详情

35.⑴A所受B的滑动摩擦力f1=μmg=0.2×2×10kg=4N          (1分)

A反作用于B的滑动摩擦力f1′=4N            (1分)

B所受地面的滑动摩擦力f2=μ(M1+m)g=0.2×(3+2)×10kg=10N     (2分)

B获得动力f1′小于受到的阻力f2,故在A滑动的过程中,B始终没有滑动(1分)

A,根据牛顿第二定律得其加速度 (2分)

1s内运动的位移             (1分)

s=L1,说明在1s末A刚好滑上C的左端      (1分)

1s末A获得的速度v1at=2×1m/s=2m/s              (1分)

⑵A滑上C之后,它对C的滑动摩擦力使C向右做匀加速运动,而CA的滑动摩擦力使A做匀减速运动,要保证A不会从C上掉下,则长木板C的最小长度L2必须符合在A滑至C的右端时双方获得共同速度v2.              (1分)

在双方相对运动的过程中所受合外力等于零,系统动量守恒,有:

 mv1=(M2+m)v2                       (2分)

又根据系统的能量守恒定律可得:

 f1L2mv12(M2+m)v22           (2分)

由以上两式解得:L2                (2分)

代入数据解得:L2=0.6m                     (1分)

试题详情

34.⑴甲(3分);先释放纸带再接通电源(3分).

⑵(I)

③作出R图象(4分)

④2.0,1.0(共2分)

(Ⅱ)如右图所示(2分)②A1;(1分)

(3分)

试题详情


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