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16.解:

(Ⅰ)由,得

,得

所以.··········································· 5分

(Ⅱ)由

由(Ⅰ)知

,······································································································· 8分

所以.····················································································· 10分

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15.3

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14.两组相对侧面分别平行;一组相对侧面平行且全等;对角线交于一点;底面是平行四边形.

注:上面给出了四个充要条件.如果考生写出其他正确答案,同样给分.

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13.

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12.2  

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11.2  

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6.D   7.B  8.B   9.B  10.C

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1.B  2.A  3.C  4.C  5.D 

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21.(本大题满分14分)

设函数.

(Ⅰ)求的单调区间;

(Ⅱ)如果对任何,都有,求a的取值范围。

麻城博达学校2010届高三阶段测试(六)

理科数学试题(B卷)

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20.(本大题满分13分)

设椭圆中心在坐标原点,A(2,0)、B(0,1)是它的两个顶点,直线与AB相交于点D,与椭圆相交于E、F两点.

(Ⅰ)若 ,求k的值;

(Ⅱ)求四边形AEBF面积的最大值.

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