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17.(本小题满分5分)

解:∵ 一次函数的图象经过点

.············································································································ 1分

解得 .··············································································································· 2分

∴ 此一次函数的解析式为.········································································ 3分

,可得

∴ 一次函数的图象与轴的交点坐标为.························································ 4分

,可得

∴ 一次函数的图象与轴的交点坐标为.·························································· 5分

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16.(本小题满分5分)

证明:在正方形ABCD中,

AB=AD=DC=BC,∠B=∠D=90O.-------------------------------------------------2分

∵  AE=AF

∴  AB-AE=AD-AF

即  BE=DF.·················································································································· 3分

在△BCE和△DCF中,

∴  △BCE≌△DCF.····································································································· 4分

∴  CECF.················································································································ 5分

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15.(本小题满分5分)

解:原式······················································································· 3分

       .·········································································································· 5分

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14.(本小题满分5分)

解:去括号,得.················································································ 1分

移项,得.························································································ 2分

合并,得.······································································································ 3分

系数化为1,得.································································································ 4分

不等式的解集在数轴上表示如图:

 

······································································································································ 5分

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13.(本小题满分5分)

解:

·································································································· 4分

.··················································································································· 5分

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25.如图,在梯形ABCD中,ADBCAD=3,CD=5,BC=10,梯形的高为4.动点MB点出发沿线段BC以每秒2个单位长度的速度向终点C运动;动点N同时从C点出发沿线段CD以每秒1个单位长度的速度向终点D运动.设运动的时间为t(秒).

(1)当MNAB时,求t的值;

(2)试探究:t为何值时,△CMN为等腰三角形.

2010年密云县初中毕业考试

数学试卷答案参考及评分标准

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24.如图,将腰长为的等腰Rt△ABC(∠C是直角)放在平面直角坐标系中的第二象限,其中点Ay轴上,点B在抛物线yax2+ax-2上,点C的坐标为(-1,0).

(1)点A的坐标为     ,点B的坐标为    

(2)抛物线的关系式为            ,其顶点坐标为      

(3)将三角板ABC绕顶点A逆时针方向旋转90°,到达的位置.请判断点是否在(2)中的抛物线上,并说明理由.

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23.已知:如图,正比例函数yax的图象与反比例函数y=的图象交于点A(3,2).

(1)试确定上述正比例函数和反比例函数的表达式;

(2)根据图象回答,在第一象限内,当x取何值时,反比例函数的值大于正比例函数的值?

(3)M(mn)是反比例函数图象上的一动点,其中0<m<3过点M作直线MBx轴,交y轴于点B;过点A作直线ACy轴交x轴于点C,交直线MB于点D.当四边形OADM的面积为6时,请判断线段BMDM的大小关系,并说明理由.

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22.(1)观察与发现:

在一次数学课堂上,老师把三角形纸片ABC(ABAC)沿过A点的直线折叠,使得AC落在AB边上,折痕为AD,展开纸片(如图①);再次折叠该三角形纸片,使点A和点D重合,折痕为EF,展平纸片后得到△AEF(如图②).有同学说此时的△AEF是等腰三角形,你同意吗?请说明理由.

(2)实践与运用

将矩形纸片ABCD沿过点B的直线折叠,使点A落在BC边上的点F处,折痕为BE(如图③);再沿过点E的直线折叠,使点D落在BE上的点处,折痕为EG(如图④);再展平纸片(如图⑤).试问:图⑤中∠的大小是多少?(直接回答,不用说明理由).

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21.为了比较市场上甲、乙两种电子钟每日走时误差的情况,从这两种电子钟中,各随机抽取10台进行测试,两种电子钟走时误差的数据如下表(单位:秒):

    编号
类型










甲种电子钟
1
-3
-4
4
2
-2
2
-1
-1
2
乙种电子钟
4
-3
-1
2
-2
1
-2
2
-2
1

(1)计算甲、乙两种电子钟走时误差的平均数;

(2)计算甲、乙两种电子钟走时误差的方差;

(3)根据经验,走时稳定性较好的电子钟质量更优.若两种类型的电子钟价格相同,请问:你用哪种电子钟?为什么?

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