解:(1)10×x=
![](http://thumb.1010pic.com/pic5/latex/729.png)
,
10×x÷10=
![](http://thumb.1010pic.com/pic5/latex/729.png)
÷10,
x=
![](http://thumb.1010pic.com/pic5/latex/48619.png)
;
(2)x+1
![](http://thumb.1010pic.com/pic5/latex/35.png)
x=
![](http://thumb.1010pic.com/pic5/latex/365.png)
,
(1++1
![](http://thumb.1010pic.com/pic5/latex/35.png)
)x=
![](http://thumb.1010pic.com/pic5/latex/365.png)
,
![](http://thumb.1010pic.com/pic5/latex/28543.png)
x=
![](http://thumb.1010pic.com/pic5/latex/365.png)
,
![](http://thumb.1010pic.com/pic5/latex/28543.png)
x÷
![](http://thumb.1010pic.com/pic5/latex/28543.png)
=
![](http://thumb.1010pic.com/pic5/latex/365.png)
÷
![](http://thumb.1010pic.com/pic5/latex/28543.png)
,
x=
![](http://thumb.1010pic.com/pic5/latex/156137.png)
;
(3)
![](http://thumb.1010pic.com/pic5/latex/1207.png)
x-
![](http://thumb.1010pic.com/pic5/latex/335.png)
x=9,
(
![](http://thumb.1010pic.com/pic5/latex/1207.png)
-
![](http://thumb.1010pic.com/pic5/latex/335.png)
)x=9,
![](http://thumb.1010pic.com/pic5/latex/38364.png)
x=9,
![](http://thumb.1010pic.com/pic5/latex/38364.png)
x÷
![](http://thumb.1010pic.com/pic5/latex/38364.png)
=9÷
![](http://thumb.1010pic.com/pic5/latex/38364.png)
,
x=
![](http://thumb.1010pic.com/pic5/latex/518671.png)
;
(4)1
![](http://thumb.1010pic.com/pic5/latex/8.png)
+3x=
![](http://thumb.1010pic.com/pic5/latex/602.png)
,
1
![](http://thumb.1010pic.com/pic5/latex/8.png)
+3x-1
![](http://thumb.1010pic.com/pic5/latex/8.png)
=
![](http://thumb.1010pic.com/pic5/latex/602.png)
-1
![](http://thumb.1010pic.com/pic5/latex/8.png)
,
3x=-
![](http://thumb.1010pic.com/pic5/latex/2367.png)
,
3x÷3=-
![](http://thumb.1010pic.com/pic5/latex/2367.png)
÷3,
x=-
![](http://thumb.1010pic.com/pic5/latex/125598.png)
.
分析:(1)根据等式的基本性质,在方程的两边同时除以10,即可求解;
(2)化简方程,根据等式的基本性质,在方程的两边同时除以
![](http://thumb.1010pic.com/pic5/latex/28543.png)
,即可求解;
(3)化简方程,根据等式的基本性质,在方程的两边同时除以
![](http://thumb.1010pic.com/pic5/latex/38364.png)
,即可求解;
(4)根据等式的基本性质,在方程的两边先同时减去1
![](http://thumb.1010pic.com/pic5/latex/8.png)
,再同时除以3,即可求解.
点评:本题主要考查了学生运用等式的性质解方程的能力.