精英家教网 > 小学数学 > 题目详情
(1+
1
2
)×(1-
1
2
)×(1+
1
3
)×(1-
1
3
)×…×(1+
1
100
)×(1-
1
100
分析:首先把括号内的加减运算完成,然后前后分子分母约分,即可得解.
解答:解:(1+
1
2
)×(1-
1
2
)×(1+
1
3
)×(1-
1
3
)×…×(1+
1
100
)×(1-
1
100

=
3
2
×
1
2
×
4
3
×
2
3
×
5
4
×
3
4
×…×
101
100
×
99
100

=
1
2
×
3
2
×
2
3
×
4
3
×
3
4
×
5
4
×…×
99
100
×
101
100

=
1
2
×
101
100

=
101
200
点评:利用分数的分数的四则混合运算,首先计算括号内的,然后约分是解决此题的关键.
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