$\frac{7}{12}$÷$\frac{1}{5}$+$\frac{5}{12}$×5 | $\frac{3}{8}$-$\frac{3}{10}$×$\frac{5}{6}$ | $\frac{7}{41}$×$\frac{1}{31}$+$\frac{34}{41}$÷31 |
$\frac{1}{5}$÷($\frac{1}{12}$+$\frac{1}{6}$)×$\frac{1}{3}$ | $\frac{1}{6}$÷$\frac{11}{24}$-$\frac{3}{8}$×$\frac{4}{11}$ | $\frac{4}{7}$÷$\frac{7}{8}$×$\frac{8}{9}$÷$\frac{4}{7}$ |
分析 (1)先变形为$\frac{7}{12}$×5+$\frac{5}{12}$×5,再根据乘法分配律计算;
(2)先算乘法,再算减法;
(3)先变形为$\frac{7}{41}$×$\frac{1}{31}$+$\frac{34}{41}$×$\frac{1}{31}$,再根据乘法分配律计算;
(4)先算小括号里面的加法,再算括号外面的除法和乘法;
(5)先算乘除法,再算减法;
(6)将除法变为乘法,再约分计算即可求解.
解答 解:(1)$\frac{7}{12}$÷$\frac{1}{5}$+$\frac{5}{12}$×5
=$\frac{7}{12}$×5+$\frac{5}{12}$×5
=($\frac{7}{12}$+$\frac{5}{12}$)×5
=1×5
=5
(2)$\frac{3}{8}$-$\frac{3}{10}$×$\frac{5}{6}$
=$\frac{3}{8}$-$\frac{1}{4}$
=$\frac{1}{8}$
(3)$\frac{7}{41}$×$\frac{1}{31}$+$\frac{34}{41}$÷31
=$\frac{7}{41}$×$\frac{1}{31}$+$\frac{34}{41}$×$\frac{1}{31}$
=($\frac{7}{41}$+$\frac{34}{41}$)×$\frac{1}{31}$
=1×$\frac{1}{31}$
=$\frac{1}{31}$
(4)$\frac{1}{5}$÷($\frac{1}{12}$+$\frac{1}{6}$)×$\frac{1}{3}$
=$\frac{1}{5}$÷$\frac{1}{4}$×$\frac{1}{3}$
=$\frac{4}{5}$×$\frac{1}{3}$
=$\frac{4}{15}$
(5)$\frac{1}{6}$÷$\frac{11}{24}$-$\frac{3}{8}$×$\frac{4}{11}$
=$\frac{4}{11}$-$\frac{3}{22}$
=$\frac{5}{22}$
(6)$\frac{4}{7}$÷$\frac{7}{8}$×$\frac{8}{9}$÷$\frac{4}{7}$
=$\frac{4}{7}$×$\frac{8}{7}$×$\frac{8}{9}$×$\frac{7}{4}$
=$\frac{64}{63}$
点评 考查了运算定律与简便运算,四则混合运算.注意运算顺序和运算法则,灵活运用所学的运算定律简便计算.
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