解:(1)0.75:1.25=x:2,
1.25x=0.75×2,
1.25x÷1.25=1.5÷1.25,
x=1.2;
(2)0.4×3-4X=0.08,
1.2-4X=0.08,
1.2-4X+4X=0.08+4X,
1.2-0.08=0.08+4X-0.08,
1.12÷4=4X÷4,
X=0.28;
(3)
![](http://thumb.1010pic.com/pic5/latex/168.png)
:
![](http://thumb.1010pic.com/pic5/latex/96.png)
=x:
![](http://thumb.1010pic.com/pic5/latex/36.png)
,
![](http://thumb.1010pic.com/pic5/latex/96.png)
x=
![](http://thumb.1010pic.com/pic5/latex/168.png)
×
![](http://thumb.1010pic.com/pic5/latex/36.png)
,
![](http://thumb.1010pic.com/pic5/latex/96.png)
x×4=
![](http://thumb.1010pic.com/pic5/latex/271308.png)
4,
x=
![](http://thumb.1010pic.com/pic5/latex/2367.png)
;
(4)x-0.8x-6=16,
0.2x-6=16,
0.2x-6+6=16+6,
0.2x÷0.2=22÷0.2,
x=110.
分析:(1)先根据比例的基本性质,把原式转化为1.25x=0.75×2,再根据等式的性质,在方程两边同时除以1.25求解.
(2)先化简,再根据等式的性质,在方程两边同时加上4X,再减去0.08,最后除以4求解.
(3)先根据比例的基本性质,把原式转化为
![](http://thumb.1010pic.com/pic5/latex/96.png)
x=
![](http://thumb.1010pic.com/pic5/latex/168.png)
×
![](http://thumb.1010pic.com/pic5/latex/36.png)
,再根据等式的性质,在方程两边同时乘上4求解.
(4)先化简,再根据等式的性质,在方程两边同时加上6,再除以0.2求解.
点评:本题主要考查了学生根据等式的性质和比例的基本性质解方程的能力,注意等号对齐.