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0.25×19+0.75×27
(96.5-96.5×0.24-0.24)÷73.1
1.25×67.875×+125×6.7875×+1250×0.053375
[20.026-(8.6+9.7)×0.92]÷3.19
1+2+3+4+…+1999
(5+9+13+…+49)-(3+7+11+…+47)
分析:(1)把0.75看作0.25×3,运用乘法分配律简算;
(2)括号内运用乘法分配律简算,进一步计算得出结果;
(3)根据数字特点,原式变为1.25×67.875×+1.25×678.75×+1.25×5.3375,运用乘法分配律简算;
(4)先算8.6+9.7=18.3,把0.92看作1-0.08,运用乘法分配律简算,这样把乘法变为加、减法,计算较简便;
(5)运用高斯求和公式简算;
(6)通过观察,发现5-3=(9-7)=…=(49-47)=2,因此把原式变为(5-3)+(9-7)+…+(49-47),计算即可.
解答:解:(1)0.25×19+0.75×27,
=0.25×19+0.25×3×27,
=0.25×19+0.25×81,
=0.25×(19+81),
=0.25×100,
=25;

(2)(96.5-96.5×0.24-0.24)÷73.1,
=[96.5-(96.5+1)×0.24]÷73.1,
=(96.5-97.5×0.24)÷73.1,
=(96.5-23.4)÷73.1,
=73.1÷73.1,
=1;

(3)1.25×67.875×+125×6.7875×+1250×0.053375,
=1.25×67.875×+1.25×678.75×+1.25×53.375,
=1.25×﹙67.875+678.75+53.375﹚,
=1.25×800,
=1000;

(4)[20.026-(8.6+9.7)×0.92]÷3.19,
=[20.026-(8.6+9.7)×0.92]÷3.19,
=[20.026-18.3×0.92]÷3.19,
=[20.026-16.836]÷3.19,
=3.19÷3.19,
=1;

(5)1+2+3+4+…+1999,
=(1+1999)×1999÷2,
=2000×1999÷2,
=1999000;

(6)(5+9+13+…+49)-(3+7+11+…+47),
=(5-3)+(9-7)+…+(49-47),
=2+2+…+2,(12个2)
=2×12,
=24.
点评:完成此题,应注意观察,认真分析式中数据,运用运算定律或运算技巧,灵活解答.
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