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(1)3.9×0.14÷(2.1×0.13)
(2)333×666+999×778
(3)198÷(198-
198
199

(4)求未知数x,
1
5
+0.3x=0.23.
分析:(1)先算小括号里面的乘法,再算括号外的乘法,最后算括号外的除法;
(2)先根据积不变规律,把333×666分解成999×222,再运用乘法分配律简算;
(3)先把括号里面的198化成假分数,再根据分数减法的计算方法,求解,然后把分子根据乘法分配律化简,再根据分数除法的计算方法求解;
(4)根据等式的性质解方程.
解答:解:(1)3.9×0.14÷(2.1×0.13),
=3.9×0.14÷0.273,
=0.546÷0.273,
=2;

(2)333×666+999×778,
=999×222+999×778,
=999×(222+778),
=999×1000,
=999000;

(3)198÷(198-
198
199
),
=198÷
199×198-198
199

=198÷
198×(199-1)
199

=198÷
198×198
199

=198×
199
198×198

=
199
198


(4  )
1
5
+0.3x=0.23,
   
1
5
+0.3x-
1
5
=0.23-
1
5

          0.3x=0.03,
     0.3x÷0.3=0.03÷0.3,
             x=0.1.
点评:完成本题要注意分析式中数据,运用合适的简便方法计算.
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