解:设乙队原有x人,
x-
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x=(210-x+
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x)×
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,
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x=
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-
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x,
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x+
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x=
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-
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x
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x,
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x
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=
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,
x=100,
210-100=110(人),
答:甲队原有110人.
分析:设乙队原有x人,甲队就有210-x人,从乙队调出
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的人去甲队后,乙队就有x-
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x人,甲队就有210-x+
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x人,此时甲乙两队人数比是4:3,也就是说乙队人数是甲队人数的
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,据此可列方程:(x-
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x)=(210-x+
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x)×
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,依据等式的性质,求出乙队原来人数,最后用总人数减乙队原有人数即可解答.
点评:解答本题用方程比较简便,只要设其中一个量是x,再用x表示出另一个量,依据数量间的等量关系列方程即可解答.