分析:(1)根据第二步17.8加几的和是20,那么所缺的数是20-17.8=2.2,然后再进一步解答;
(2)根据第二步小括号里面的几加21.35的和是50,那么所缺的数是50-21.35=28.65,然后再进一步解答;
(3)根据第二步小括号里面的几加9.23的和是10,那么所缺的数是10-9.23=0.77,然后再进一步解答;
(4)根据第二步33.25减几的差是30,那么所缺的数是33.25-30=3.25,然后再进一步解答.
解答:解:
(1)18.7-16.4+2.2,
=18.7+2.2-l6.4,
=20-16.4,
=3.6;
(2)35.67+28.65+21.35,
=35.67+( 28.65+21.35),
=35.67+50,
=85.67;
(3)54.37-0.77-9.23,
=54.37-( 0.77+9.23),
=54.37-10,
=44.37;
(4)33.25+6.23-3.25,
=33.25-3.25+6.23,
=30+6.23,
=36.23.
故答案为:2.2,2.2,3.6,28.65,28.65,85.67,0.77,0.77,44.37,3.25,3.25,36.23.
点评:本题的关键是根据关键的步骤,求出所缺的数,然后再进一步解答.