解:(1)10(200X+X)=11×200X-22.8,
2010X=2200X-22.8,
2010X-2010X=2200X-22.8-2010X,
190X-22.8=0,
190X-22.8+22.8=0+22.8,
190X=22.8,
190X÷190=22.8÷190,
X=0.12;
(2)
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=3+
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,
5X-10=3+2X+2,
5X-10+10=3+2X+2+10,
5X=2X+15,
5X-2X=2X+15-2X,
3X=15,
3X÷3=15÷3,
X=5.
分析:(1)原式变为2010X=2200X-22.8,根据等式的性质,两边同减去2010X,得190X-22.8=0,两边同加上22.8,再同除以190即可;
(2)化简原式为5X-10=3+2X+2,根据等式的性质,两边同加10,得5X=2X+15,两边同减2X,得3X=15,再同除以3即可.
点评:此题考查了根据等式的性质解方程,即等式两边同加、同减、同乘或同除以一个数(0除外),等式的左右两边仍相等;注意等号上下要对齐.