考点:2、3、5的倍数特征,奇数与偶数的初步认识
专题:整数的认识,数的整除
分析:(1)个位数是奇数3即可;
(2)个位是偶数0或2或4即可;
(3)3的倍数:各个数位上的和能被3整除;
(4)5的倍数:末尾是0即可;
(5)个位是0即可;
解答:
解:(1)首先满足个位数字是3即可:203,243,403,423;
(2)个位数字应该是0,2,4的:302,320,402,420,234,432,342,324,230,204,240,304,340,430;
(3)各个数位上的数相加之和是3的倍数即可:230,240,320,340,420,430;
(4)个位数字是0:230,240,320,340,420,430;
(5)既是2的倍数,又是5的倍数:230,240,320,340,420,430;
故答案为:(1)203,243,403,423;
(2)302,320,402,420,234,432,342,324,230,204,240,304,340,430
(3)230,240,320,340,420,430.;
(4)230,240,320,340,420,430.;
(5)230,240,320,340,420,430.
点评:解答此题应根据题意,根据能被奇数、偶数的概念,及能被2、3、5、整除数的特征进行解答即可.