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(0.12+0.23+0.34)×(0.23+0.34+0.45)-(0.12+0.23+0.34+0.45)×(0.23+0.34)=
0.054
0.054
分析:通过观察,此题数字有一定特点,可用设数法解答,假设A=0.12+0.23+0.34,B=0.23+0.34.原式变为A×(B+0.45)-(A+0.45)×B=0.45×(A-B),把A=0.12+0.23+0.34,B=0.23+0.34代入上式,化简即可.
解答:解:假设A=0.12+0.23+0.34,B=0.23+0.34    
原式=A×(B+0.45)-(A+0.45)×B,
=AB+0.45A-AB-0.45B,
=0.45×(A-B);
把A=0.12+0.23+0.34,与B=0.23+0.34代入上式得:
0.45×(0.12+0.23+0.34-0.23-0.34),
=0.45×0.12,
=0.054.
点评:此题根据数字特点,采用设数法解答,比较简便.
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