解:根据题意可得:
(1)x-16×3=102,
x-48=102,
x-48+48=102+48,
x=150;
(2)
![](http://thumb.1010pic.com/pic5/latex/168.png)
:x=
![](http://thumb.1010pic.com/pic5/latex/96.png)
:9,
![](http://thumb.1010pic.com/pic5/latex/96.png)
x=9×
![](http://thumb.1010pic.com/pic5/latex/168.png)
,
![](http://thumb.1010pic.com/pic5/latex/96.png)
x=6,
![](http://thumb.1010pic.com/pic5/latex/96.png)
x÷
![](http://thumb.1010pic.com/pic5/latex/96.png)
=6÷
![](http://thumb.1010pic.com/pic5/latex/96.png)
,
x=24;
(3)
![](http://thumb.1010pic.com/pic5/latex/66682.png)
=x:10,
4.5x=0.8×10,
4.5x=8;
4.5x÷4.5=8÷4.5;
x=
![](http://thumb.1010pic.com/pic5/latex/731.png)
;
(4)1.2x+4.6=6.4,
1.2x+4.6-4.6=6.4-4.6,
1.2x=1.8,
1.2x÷1.2=1.8÷1.2,
x=1.5.
分析:(1)先计算16×3=48,然后等式的两边同时加上48即可;
(2)根据比例的基本性质,两内项之积等于两外项之积,把原式改写成
![](http://thumb.1010pic.com/pic5/latex/96.png)
x=9×
![](http://thumb.1010pic.com/pic5/latex/168.png)
,然后等式的两边同时除以
![](http://thumb.1010pic.com/pic5/latex/96.png)
即可;
(3)根据比例的基本性质,两内项之积等于两外项之积,把原式改写成4.5x=0.8×10,然后等式的两边同时除以4.5即可;
(4)等式的两边同时减去4.6,然后等式的两边再同时除以1.2即可.
点评:本题主要考查解比例和解方程,根据比例的基本性质和等式的性质进行解答即可.