分析:(1)据乘法算式的性质将原式变为0.125×10+3.96×12.5%+2.04×0.125后再据分配律进行简便运算;
(2)根据分配律将105×36变为(100+5)×36再据减法性质进行计算;
(3)可先据分配律将式中84
÷7拆分为(84+
)÷7再据减法性质进行简便计算;
(4)可将括号中的算式据分配律进行简便计算;
(5)将据分配律进行简便计算.
解答:解:(1)10÷8+3.96×12.5%+2.04×
=1.25+3.96×12.5%+2.04×0.125,
=0.125×10+3.96×0.125+2.04×0.125,
=(10+3.96+2.04)×0.125,
=16×0.125,
=2;
(2)6000-105×36
=6000-(100+5)×36,
=6000-100×36-36×5,
=6000-3600-180,
=2220;
(3)85-84
÷7
=85-(84+
)÷7,
=85-84÷7-
÷7,
=85-12-
,
=72
;
(4)
÷[(+)×]=
÷[
×+
×],
=
÷[
+
],
=
×
,
=
;
(5)
1×3.6+3×7+3.6=1
×3.6+3.6×7
+3.6,
=(1
+7
+1)×3.6,
=10×3.6,
=36.
点评:完成此类题目要认真分析式中据,根据式中数据的特点及内在联系选择合适的方法进行简便计算.